MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4

पाठ्य-पुस्तक पृष्ठ संख्या # 191-192

प्रश्न 1.
दशमलव का प्रयोग कर Rs में बदलिए
(a) 5 पैसे
(b) 75 पैसे
(c) 20 पैसे
(d) 50 रुपये 90 पैसे
(e) 725 पैसे।
हल :
(a) 5 पैसे = Rs \(\frac { 5 }{ 100 }\) = Rs 0.05
(∵ 1 पैसा = Rs \(\frac { 1 }{ 100 }\))

(b) 75 पैसे = Rs \(\frac { 75 }{ 100 }\) = Rs 0.75

(c) 20 पैसे = Rs \(\frac { 20 }{ 100 }\) = Rs 0.20

(d) 50 रुपये 90 पैसे = 50 + \(\frac { 90 }{ 100 }\)
= 50 + 0.90
= Rs 50.90

(e) 725 पैसे = Rs \(\frac { 725 }{ 100 }\)
= \(\frac{700}{100}+\frac{25}{100}\)
= 7 + 0.25
= Rs 7.25

प्रश्न 2.
दशमलव का प्रयोग कर मीटर में व्यक्त कीजिए
(a) 15 सेमी,
(b) 6 सेमी
(c) 2 मीटर 45 सेमी
(d) 9 मीटर 7 सेमी
(e) 419 सेमी
हल :
∵100 सेमी = 1 मीटर
∴1 सेमी = \(\frac { 1 }{ 100 }\) मीटर

(a) 15 सेमी = 15 x \(\frac { 1 }{ 100 }\) मीटर
= \(\frac { 15 }{ 100 }\) मीटर
= 0.15 मीटर

(b) 6 सेमी = 6 x \(\frac { 1 }{ 100 }\) मीटर
= \(\frac { 6 }{ 100 }\) मीटर
= 0.06 मीटर

(c) 2 मीटर 45 सेमी = 2 मीटर + 45 x \(\frac { 1 }{ 100 }\) मीटर
= 2 मीटर + \(\frac { 45 }{ 100 }\) मीटर
= 2 मी. + 0.45 मी
= 2.45 मी

(d) 9 मीटर 7 सेमी = 9 मी + 7 x \(\frac { 1 }{ 100 }\) मी
= 9 मी + \(\frac { 7 }{ 100 }\) मी
= 9 मी + 0.07 मी
= 9.07 मी

(e) 419 सेमी = 419 x \(\frac { 1 }{ 100 }\) मी
= \(\frac { 400 }{ 100 }\) मी + \(\frac { 19 }{ 100 }\) मी
= 4 मी + 0.19 मी
= 4.19 मी

MP Board Solutions

प्रश्न 3.
दशमलव का प्रयोग कर सेमी में बदलिए
(a) 5 मिमी
(b) 60 मिमी
(c) 164 मिमी
(d) 9 सेमी 8 मिमी
(e) 93 मिमी
हल :
∵10 मिमी = 1 सेमी
∴1 मिमी = \(\frac { 1 }{ 10 }\) सेमी

(a) 5 मिमी = 5 x \(\frac { 1 }{ 10 }\) सेमी
= \(\frac { 5 }{ 10 }\) सेमी
= 0.5 सेमी

(b) 60 मिमी = 60 x \(\frac { 1 }{ 10 }\) सेमी
= \(\frac { 60 }{ 10 }\) सेमी
= 6 सेमी

(c) 164 मिमी = 164 x \(\frac { 1 }{ 10 }\) सेमी
= \(\frac { 164 }{ 10 }\) सेमी
= \(\frac { 160+4 }{ 10 }\) समा
= \(\frac { 160 }{ 10 }\) सेमी + \(\frac { 4 }{ 10 }\) सेमी
= 16 सेमी + 0.4 सेमी
= 16.4 सेमी

(d) 9 सेमी 8 मिमी = 9 सेमी + 8 x \(\frac { 1 }{ 10 }\) सेमी
= 9 सेमी + \(\frac { 8 }{ 10 }\) सेमी
= 9 सेमी + 0.8 सेमी
= 9.8 सेमी

(e) 93 मिमी = 93 x \(\frac { 1 }{ 10 }\) सेमी
= \(\frac { 90 }{ 10 }\) सेमी + \(\frac { 3 }{ 10 }\) सेमी
= 9 सेमी + 0.3 सेमी
= 9.3 सेमी

प्रश्न 4.
दशमलव का प्रयोग कर किमी में लिखिए
(a) 8 मी
(b) 88 मी
(c) 8888 मी
(d) 70 किमी 5 मी
हल :
:: 1000 मीटर = 1 किमी,
1 मीटर = \(\frac { 1 }{ 1000 }\) किमी

(a) 8 मी = 8 x \(\frac { 1 }{ 1000 }\) किमी
= \(\frac { 8 }{ 1000 }\) किमी
= 0.008 किमी

(b) 88 मी. = 88 x \(\frac { 1 }{ 1000 }\) किमी
= \(\frac { 88 }{ 1000 }\) किमी
= 0.088 किमी

(c) 8888 मी = 8888 x \(\frac { 1 }{ 1000 }\) किमी
= \(\frac { 8000 }{ 1000 }\) कमा + \(\frac { 888 }{ 1000 }\) किमा
= 8 किमी + 0.888 किमी
= 8.888 किमी

(d) 70 किमी 5 मी = 70 किमी + 5 मी.
= 70 किमी + \(\frac { 5 }{ 1000 }\) किमी
= 70 किमी + 0.005 किमी
= 70.005 किमी

MP Board Solutions

प्रश्न 5.
दशमलव का प्रयोग कर किग्रा में लिखिए
(a) 2 ग्रा
(b) 100 ग्रा
(c) 3750 ग्रा
(d) 5 किग्रा 8 ग्रा
(e) 26 किग्रा 50 ग्रा।
हल :
1 किग्रा = 1000 ग्रा
1 ग्रा = \(\frac { 1 }{ 1000 }\) किग्रा

(a) 2 ग्रा = \(\frac { 2 }{ 1000 }\) किग्रा
= 0.002 किग्रा

(b) 100 ग्रा = \(\frac { 100 }{ 1000 }\) किग्रा
= 0.1 किग्रा

(c) 3750 ग्रा = \(\frac { 3750 }{ 1000 }\) किग्रा
= \(\frac { 3000 }{ 1000 }\) किग्रा + \(\frac { 750 }{ 1000 }\) किग्रा
= 3 किग्रा + 0.750 किग्रा
= 3.750 किग्रा

(d) 5 किग्रा 8 ग्रा = 5 किग्रा + 8 ग्रा
= 5 किग्रा + \(\frac { 8 }{ 1000 }\) किग्रा
= 5.008 किग्रा

(e) 26 किग्रा 50 ग्रा = 26 किग्रा + 50 ग्रा
= 26 किग्रा + \(\frac { 50 }{ 1000 }\) किग्रा
= 26 किग्रा + 0.050 किग्रा
= 26.050 किग्रा

पाठ्य-पुस्तक पृष्ठ संख्या # 193

प्रयास कीजिए

MP Board Solutions

प्रश्न 1.
ज्ञात कीजिए
(i) 0.29 + 0.36
(ii) 0.7 + 0.08
(iii) 1.54 + 1.80
(iv) 2.66 + 1.85
हल :
(i) 0.29 + 0.36
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4 image 1
अतः 0.29 + 0.36 = 0.65

(ii) 0.7 + 0.08
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4 image 2
अतः 0.7 + 0.08 = 0.78

(iii) 1.54 + 1.80
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4 image 3
अतः 1.54 + 1.80 = 3.34

(iv) 2.66 + 1.85
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.4 image 4
अत: 2.66 + 1.85 = 4.51

MP Board Class 6th Maths Solutions

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3

पाठ्य-पुस्तक पृष्ठ संख्या # 190

प्रश्न 1.
कौन-सी बड़ी है ? कारण भी लिखिए
(a) 0.3 या 0.4
(b) 0.07 या 0.02
(c) 3 या 0.8
(d) 0.5 या 0.05
(e) 1.23 या 1.2
(f) 0.099 या 0.19
(g) 1.5 या 1.50
(h) 1.431 या 1.490
(i) 3.3 या 3.300
(j) 5.64 या 5.603
(k) पाँच ऐसे ही उदाहरण लिखकर उनमें से बड़ी संख्या ज्ञात कीजिए।
हल :
(a) 0.3 = \(\frac { 3 }{ 10 }\) और 0.4 = \(\frac { 4 }{ 10 }\)
∵ 0.3 का दशांश स्थान का अंक (3) 0.4 के दशांश स्थान के अंक (4) से छोटा है। :
∴0.3 < 0.4 अर्थात् 0.4 > 0.3

(b) 0.07 = \(\frac { 7 }{ 100 }\) और 0.02 = \(\frac { 2 }{ 100 }\)
∵ 0.07 की शतांश स्थान का अंक (7) 0.02 के शतांश स्थान के अंक (2) से बड़ा है। (7 > 2)
∴ 0.07 > 0.02

(c) 3 = 3 + \(\frac { 0 }{ 10 }\) और 0.8 = 0 + \(\frac { 8 }{ 10 }\).
∵ 3 का पूर्ण भाग 0.8 से बड़ा है। (3 > 0)
∴ 3 > 0.8

(d)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 1
∵ 0.5 का दशांश स्थान का अंक (5) 0.05 के दशांश स्थान के अंक (0) से बड़ा है। (5 > 0)
∴ 0.5 > 0.05

(e)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 2
∵ 1.23 का शतांश स्थान का अंक (3) 1.2 के शतांश स्थान के अंक (0) से बड़ा है। (3 > 0)
∴ 1.23 > 1.2

(f)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 3
∵ 0.099 का दशांश स्थान का अंक (0) 0.19 के दशांश के अंक (1) से छोटा है। (0 < 1)
∴ 0.099 < 0.19 अर्थात् 0.19 > 0.099

(g)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 4
∵ इस स्थिति में दोनों संख्या ओं का भाग पूर्णतः समान है।
∴ दोनों संख्याएँ समान हैं।

(h)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 5
∵ 1.431 का शतांश स्थान का अंक (3) 1.490 के शतांश स्थान के अंक (9) से छोटा है। (3 > 9)
∴ 1.431 < 1.490. अर्थात् 1.490 > 1.431

(i)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 6
∵ इस स्थिति में दोनों संख्याओं का भाग पूर्णतः समान है।
∴ 3.3 और 3.300 समान हैं।

(j)
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 7
∵ 5.64 का शतांश स्थान का अंक (4) 5.603 के शतांश स्थान के अंक (0) से बड़ा है। (4 > 0)
∴ 5.64 > 5.603

MP Board Solutions

(k) उदाहरण
(i) 1.08 या 1.082
(ii) 1.0 या 0.99
(iii) 13.55 या 13.5
(iv) 4.03 या 4.30
(v) 11.21 या 11.12
यहाँ,
(i) 1.082 > 1.08,
(ii) 1.0 > 0.99,
(iii) 13.55 > 13.5,
(iv) 4.30 > 4.03,
(v) 11.21 > 11.12.

प्रयास कीजिए .

प्रश्न 1.
(i) 2 रुपये 5 पैसे और 2 रुपये 50 पैसों को दशमलव में लिखिए।
(ii) 20 रुपये 7 पैसे और 21 रुपये 75 पैसों को दशमलव में लिखिए।
हल :
(i) 2 रुपये 5 पैसे = 2 रुपये + \(\frac { 5 }{ 100 }\) रुपये
= 2 रुपये + 0.05 रुपये
= 2.05 रुपये
2 रुपये 50 पैसे = 2 रुपये + \(\frac { 50 }{ 100 }\) रुपये
= 2 रुपये + 0.50 रुपये
= 2.50 रुपये

(ii) 20 रुपये 7 पैसे = 20 रुपये + \(\frac { 7 }{ 100 }\) रुपये
= 20 रुपये + 0.07 रुपये
= 20.07 रुपये
21 रुपये 75 पैसे = 21 रुपये + \(\frac { 75 }{ 100 }\) रुपये
= 21 रुपये + 0.75 रुपये
= 21.75 रुपये

पाठ्य-पुस्तक पृष्ठ संख्या # 191

प्रयास कीजिए

प्रश्न 1.
क्या 4 मिमी को दशमलव का प्रयोग कर सेमी में लिख सकते हैं?
हल :
हाँ, 4 मिमी = \(\frac { 4 }{ 10 }\) सेमी = 0.4 सेमी

प्रश्न 2.
7 सेमी 5 मिमी को दशमलव का प्रयोग कर सेमी में कैसे लिखेंगे?
हल :
7 सेमी 5 मिमी = 7 सेमी + \(\frac { 5 }{ 10 }\) सेमी
= 7 सेमी + 0.5 सेमी
= 7.5 सेमी

प्रश्न 3.
क्या अब आप 52 मी को दशमलव का प्रयोग कर किमी में लिख सकते हैं? दशमलव का प्रयोग कर 340 मीटर को किमी में कैसे लिखेंगे ? 2008 मी को किमी में कैसे लिखेंगे?
हल :
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.3 image 8

MP Board Solutions

प्रयास कीजिए

प्रश्न 1.
क्या आप 456 ग्रा को दशमलव का प्रयोग कर किग्रा में लिख सकते हैं ?
हल :
हाँ 456 ग्रा = \(\frac { 456 }{ 1000 }\) किग्रा = 0.456 किग्रा

प्रश्न 2.
2 कि 9 ग्राम को दशमलव का प्रयोग कर किग्रा में कैसे लिख सकते हैं ?
हल :
2 कि 9 ग्राम = 2 किग्रा + 9 ग्राम
= 2 किग्रा + \(\frac { 9 }{ 1000 }\) किग्रा
= 2 किग्रा + 0.009 किग्रा
= 2.009 किग्रा

MP Board Class 6th Maths Solutions

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2

पाठ्य-पुस्तक पृष्ठ संख्या # 187-188

प्रश्न 1.
पाठ्य-पुस्तक में दिये गये बाक्सों की सहायता से सारणी को पूरा कर दशमलव रूप में लिखिए :
हल :
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 1

प्रश्न 2.
स्थानीय मान सारणी को देखकर दशमलव रूप में लिखिए
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 2
हल:
(i) दशमलव रूप = 0 x 100 + 0 x 10 + 3 x 1 + 2 x \(\frac { 1 }{ 10 }\) + 5 x \(\frac { 1 }{ 100 }\) + 0 x \(\frac { 1 }{ 1000 }\)
= 0 + 0 + 3 + \(\frac { 2 }{ 10 }\) + \(\frac { 5 }{ 100 }\) + 0
= 3 + 0.2 + 0.05
= 3.25

(ii) दशमलव रूप = 1 x 100 + 0 x 10 + 2 x 1 + 6 x \(\frac { 1 }{ 10 }\) + 3 x \(\frac { 1 }{ 100 }\) + 0 x \(\frac { 1 }{ 1000 }\)
= 100 + 0 + 2 + \(\frac { 6 }{ 10 }\) + \(\frac { 3 }{ 100 }\) + 0.
= 102 + 0.6 + 0.03
= 102.63

(iii) दशमलव रूप = 0 x 100 + 3 x 10 + 0 x 1 + 0 x \(\frac { 1 }{ 10 }\) + 2 x \(\frac { 1 }{ 100 }\) + 5 x \(\frac { 1 }{ 1000 }\)
= 0 + 30 + 0 + 0 + \(\frac { 2 }{ 100 }\) + \(\frac { 5 }{ 1000 }\)
= 30 + 0.02 + 0.005
= 30.025

MP Board Solutions

(iv) दशमलव रूप = 2 x 100 + 1 x 10 + 1 x 1 + 9 x \(\frac { 1 }{ 10 }\) + 0 x \(\frac { 1 }{ 100 }\) + 2 x \(\frac { 1 }{ 1000 }\)
= 200 + 10 + 1 + \(\frac { 9 }{ 10 }\) + 0 + \(\frac { 2 }{ 1000 }\)
= 211 + 0.9 + 0 + 0.002
= 211.902

(v) दशमलव रूप = 0 x 100 + 1 x 10 + 2 x 1 + \(\frac { 1 }{ 10 }\) + 4 x \(\frac { 1 }{ 100 }\) + 1 x \(\frac { 1 }{ 1000 }\)
= 0 + 10 + 2 + \(\frac { 2 }{ 10 }\) + \(\frac { 4 }{ 100 }\) + \(\frac { 1 }{ 1000 }\)
= 12 + 0.2 + 0.04 + 0.001
= 12.241

प्रश्न 3.
निम्न दशमलवों को स्थानीय मान सारणी बनाकर लिखिए
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812
हल:
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 3

प्रश्न 4.
निम्न में से प्रत्येक को दशमलव रूप में लिखिए
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 4
हल :
(a) \(20+9+\frac{4}{10}+\frac{1}{100}\)
= 29 + 0.4 + 0.01
= 29.41

(b) \(137+\frac{5}{100}\)
= 137 + 0-05
= 137.05

(c) \(\frac{7}{10}+\frac{6}{100}+\frac{4}{1000}\)
= 0.7 + 0.06 + 0.004
= 0.764

(d) \(23+\frac{2}{10}+\frac{6}{1000}\)
= 23 + 0.2 + 0.006
= 23.206

MP Board Solutions

(e) \(700+20+5+\frac{9}{100}\)
= 725 + 0.09
= 725.09

प्रश्न 5.
निम्न दशमलवों को शब्दों में लिखिए
(a) 0.03
(b) 1.20
(c) 108.56
(d) 0.032
(e) 5.008
हल :
(a) 0.03 → शून्य दशमलव शून्य तीन
(b) 1.20 → एक दशमलव दो शून्य
(c) 108.56 → एक सौ आठ दशमलव पाँच छः
(d) 0.032 → शून्य दशमलव शून्य तीन दो
(e) 5:008 → पाँच दशमलव शून्य शून्य आठ

प्रश्न 6.
संख्या रेखा के किन दो बिन्दुओं के बीच निम्न संख्याएँ स्थित हैं ?
(a) 0.06
(b) 0.45
(c) 0.19
(d) 0.66
(e) 0.92
(f) 0.57
हल :
(a) 0.06 स्थित है 0 और 0.1 के बीच में
(b) 0.45 स्थित है 0.4 और 0.5 के बीच में
(c) 0.19 स्थित है 0.1 और 0.2 के बीच में
(d) 0.66 स्थित है 0.6 और 0.7 के बीच में
(e) 0.92 स्थित है 0.9 और 1.0 के बीच में
(f) 0.57 स्थित है 0.5 और 0.6 के बीच में।

प्रश्न 7.
न्यूनतम रूप में भिन्न बनाकर लिखिए
(a) 0.60
(b) 0.05
(c) 0.75
(d) 0.18
(e) 0.25
(f) 0.125
(g) 0.066
हल :
(a) 0.60
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 5

(b) 0.05
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 6

MP Board Solutions

(c) 0.75
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 7

(d) 0.18
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 8

(e) 0.25
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 9

(f) 0.125
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 10

(g) 0.066
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.2 image 11

MP Board Class 6th Maths Solutions

MP Board Class 6th Social Science Solutions Miscellaneous Questions 3

MP Board Class 6th Social Science Solutions Miscellaneous Questions 3

MP Board Class 6th Social Science Miscellaneous Questions 3 Short Answer Type Questions

Question 1.
Who was the last ruler of the Mauryan Dyanasty?
Answer:
The last ruler of the Mauryan Dynasty was Brahdrath.

Question 2.
What is meant by Sangam Literature?
Answer:
Three literary councils were held in Madurai town. In the second council, two thousand poems were compiled into 8 books. These books are called the ‘Sangam Sahitya’. Sangam Sahitya is written in Tamil.

Question 3.
The Kings of which dynasty built the Rath temples of Mahabalipuram?
Answer:
Pallavas

MP Board Solutions

Question 4.
Which God did Alwar worship?
Answer:
Vishnu.

Question 5.
Write the name of the famous king of the Chola Dynasty?
Answer:
Ader was the famous king of the Chola Dynasty.

Question 6.
Write the names of two rulers of the Pallava Dynasty?
Answer:
The famous rulers of the Pallavas Dynasty were Mahendra Varman – I, Narsingh Varman – I and Narsingh Varman – II.

Question 7.
Which kingdom was ruled by Pulkeshin – II?
Answer:
Pulakeshin – II was Harsha’s contemporary king who ruled over Vatapi in South India.

Question 8.
Who was Fa – Hien? In whose regin did he come to India?
Answer:
Fa – Hien was a Chinese traveller who came to India during the reign of Gupta. He wrote a vivid account of the administration of Gupta period.

Question 9.
What was the ancient name of Thailand?
Answer:
The ancient name of Thailand was Shyam.

Question 10.
Who is the Chief Executive officer of a Nagar Panchayat?
Answer:
The Chief Administrative officer of the Nagar Panchayat is the Chief Executive officer. His job is to take action on the decisions taken by the Nagar Panchayat.

MP Board Solutions

Question 11.
What are the members of a Municipality called?
Answer:
Counsellars.

Question 12.
Write any two functions of the Zila Panchayat?
Answer:

  1. The main function of the Zila Panchayat is to look after the working of the Janpad and Gram Panchayat.
  2. It makes arrangements for the required finance for the Janpad and Gram Panchayat.
  3. It coordinates the different government departments.
  4. It also appoints people on certain posts.

Question 13.
What is the difference between civil and criminal cases?
Answer:
The civil cases are related to property and money disputes. These are heard in Civil Courts (Civil Judge).

Question 14.
Where is the high Court of Madhya Pradesh?
Answer:
Jabalpur.

Question 15.
Write the names of the two cities where the branches of the Madhya Pradesh High Court are situated?
Answer:
Indoreand Gwalior.

MP Board Solutions

Question 16.
Write the difference between Rabi and Kharif corps?
Answer:
1. Kharif Crops:
These are sown in June and July. For example: Jowar (Sorghum), Maize, Urad, Moong, Soyabeen Groundnut etc. October and December. For example: Wheat, Gram, Barley, Sweetpeas, Mustard and Barseem etc.

2. Rabi Crops:
These are sown between October and December. For example: Wheat, Gram, Barley, Sweetpeas, Mustard and Barseem etc.

3. Summer Crops:
These are sown between February and March. For example: Water Melon, Bitter gourd, Snake gourd.

Question 17.
What do you understand by fibrous corps? Give examples?
Answer:
Cotton and jute are two crops which give fibres. The cotton plant grows well is the black soil of Deccan Plateau and it also gets enough sunlight. Cotton is produced in Andhra Pradesh, Gujarat and Maharashtra while jute is produced in the delta of the Ganga in West Bengal.

Question 18.
What are the sources of power?
Answer:
The resources that generate energy are called sources of power. These are coal, mineral oil, natural gas, hydro – electricity, atomic minerals, etc.

Question 19.
Which route mainly connects India to the neighbouring countries?
Answer:
Sea routes.

Question 20.
What do you understand by harbours?
Answer:
A harbour is a place on the sea coast where ship carry goads and passengers from the harbours to other harbours.

MP Board Solutions

Question 21.
What did Huen – Tsang write about India? Describe?
Answer:
Huen – Tsang was a Chinese traveller. He travelled in India for many years and then went back to China. According to Huen – Tsang Buddhist religion was popular in eastern India. He also visited Nalanda. The descriptions of Huen – Tsang show that people at the time of Harsha was happy and prosperous. The rich and the poor, all lived with religious tolerance and harmony. Some people took both the vegetarian and non vegetarian meals. People were hot tempered but honest. Death sentence was not given in the state of Harsha.

Question 22.
Write the names of the famous rulers of the Chola Dynasty?
Answer:
Ader was the famous king of the Chola Dynasty.

Question 23.
Write the names of the famous rulers of the Pallava Dynasty?
Answer:
The famous rulers of the Pallavas Dynasty were Mahendra Varman – I, Narsingh Varman – I and Narsingh Varman – II.

Question 24.
Who did Pulikeshin – II defeat?
Answer:
Narshing Varman-I defeated the Chalukya King Pulkeshin – II.

MP Board Class 6th Social Science Miscellaneous Questions 3 Long Answer Type Questions

Question 1.
Describe the victories of Harsh – vardhan?
Answer:
Harshvardhana made Kannauj his capital and thus Thanesvara and Kannauj became one. Harsha conquered Punjab, Eastern Rajasthan, Assam and regions in the Gangetic valleys and annexed them to his kingdom. Harsha’s empire extended over Magadha, Eastern Bengal, Orissa, Gujarat, Saurashtra, Sindh and Malwa.

MP Board Solutions

Question 2.
Write short notes on:

  1. Relation of India with the Western Countries.
  2. Relation of India with the Arabian Countries.
  3. Relation of India with Centra, Asia.
  4. Relation of India with china.

Answer:
1. The relation of India with Western Countries:
The excavation of Harappan civilisation has provided the in formation that India had trade and cultural relations with Mesopotamia since 3000 BC. Even before 600 BC India had relation with Arabs, Greeks and Romans. Relation were made with the Greeks after the invasion of Alexander. Megasthnese was the Greek ambassador in in the court of Chandra Gupta Maura.

The Historian Pleeny was very much upset due to the increase in the import of silk, cotton, jwellery and spices. The import of these goods caused a lot of Roman wealth reach India. The persons who came from abroad were called ‘Yavan’ in ‘Sangam Sahitya’. There was a habitation of Roman in Aricmendu in Tamil Nadu.

2. Relation of India with the Arabian Countries:
The relation of India with the Arabian Coipitries is quite old. The Arabs learnt the Indian numerical system and the decimal system from India. They called the Indian numerical system the Hindsa. The Europeans received this knowledge from the Arabs.

Therefore they call this numerical system Arabic. After the emergence of Islam, the Arabs captured the land route between India and Europe. Thus they became a link between India and Europe. In olden times Arabs came to India to study science. Mathematics, Astrology, Medicine, Philosophy and Literature.

3. Relation of India with Central (Middle):
The cities of Khotan, Kuchi, Caiso and Kashgar were situated in hilly areas. Therefore they were not in easy reach. But they had trade and cultural relations with each other. In Mahabharata Dhritrashtra’s wife was Gandhari. Gandhari was situated here. Now it is called Afganistan. Gandhar was the main centre fo Buddhism. The oldest statues of Buddha were made here. Emperor Ashoka had sent his preachers to Middle Asia also. Two records have been found here which prove this.

In the southern parts of Russia too we get the proofs of Indian civilisation. The excavation at Surkhan river and Dalverjin Tepe in the south of Ujbekistan gives information about the development of art during the Kushan period and the effect of the Indian culture on it.

4. India’s relation with China:
The Buddhist religion of India reached China during the period of Huan Dynasty (202 BC to 600 AD) Buddhism was preached at Khotan (a place between India and China). Buddhism spread in China from this place. The people of China had started coming to India from 2nd century B.C. for education and to get knowledge of Buddhism. Kashyap matang was the first person to the first translate the Buddhist religious books into Chinese. He had gone to China in 56 AD. Buddhism spread in 372 AD to Korea From China and from there it spread to Japan in 538 AD.

Amodhbajra was an Indian Buddhist writer who went the China in 8th century. Many Chinese scholars travelled in India. Fattien travelled in India during the reign of Chandragupta – II (405-411 AD) stayed in India for 6 years. The next traveller Huen – Sang came to India during the region of Harshavardhan.

MP Board Solutions

Question 3.
What do you understand by the three – tier Panchayati Raj system? Describe the constitution of Gram Panchayat and Zila Panchayat?
Answer:
That part of the local self government which runs the administration of the rural areas is called Panchayati Raj. In the system, the villagers run their own affairs. Panchayati decides most of the village disputes. The Panchayati Raj System consists of Village Panchayat, Block Samiti and Zilla Panchayati. There are three institutions that work for the development of the rural areas. They are:
1. Gram Panchayat:
It works at the village level.

2. Janpad Panchayat:
All the Village Panchayats join together to form a Janpad Panchayat. These are formed at the Block level.

3. Zilla Panchayat:
The highest body in the three – tier Panchayti Raj system is the Zila Panchayat. It works at the district level. Therefore all the Janpad Panchayat of the district are under the Zilla Panchayat. The above three institutions of local government are called the Panchayati Raj.

Question 4.
Where and how is a Municipality constituted?
Answer:
The local bodies function with the help of income from the following sources:

  1. Property tax on house, land etc.
  2. Tax on trade and business.
  3. Fees on water facilities.
  4. Fees on electricity facilities.
  5. Income and rent earned from the institutions, property like the buildings, markets, etc.
  6. Grants from the state government.
  7. Income from various kinds of fine on pets or stray animals etc.

Question 5.
Explain the constitution of a Municipal Corporation?
Answer:
The corporation is established in large cities. The head of a corporation is the Mahapaur or Mayor. He is elected by the members of the corporation. Besides the Mayor, a Deputy Mayor is also elected. The number of elected members is generally between fifty and one hundred fifty. They are elected for a term of five years on the basis of adult franchise. These representatives elected by the people, sometime elect special members called the Elderman.

MP Board Solutions

Question 6.
State the divisions of India as per Neutral Vegetation and describe any one of them?
Answer:
The major forests of India are the following:

  1. Tropical Evergreen or Rain Forests
  2. Tropical Deciduous Forests or Monsoon Forests
  3. Thorn Forests and Bushes
  4. Mangrove Forests

Question 7.
Write short notes on:

  1. Tropical Deciduous forests.
  2. Mangrove forests.

Answer:
The major forests of India are the following:

  1. Tropical Evergreen or Rain Forests
  2. Tropical Deciduous Forests or Monsoon Forests
  3. Thorn Forests and Bushes
  4. Mangrove Forests

The major forests of India are the following:

  1. Tropical Evergreen or Rain Forests
  2. Tropical Deciduous Forests or Monsoon Forests
  3. Thorn Forests and Bushes
  4. Mangrove Forests

Question 8.
Describe the minerals found in India?
Answer:
The following minerals are found in India: Iron, magnese, copper, lead, mica, zinc, gold and bauxite etc.

Question 9.
Write the characteristics of the Indian Population?
Answer:
The main scheduled tribes lived in Madhya Pradesh are Bhil, Kir, Nehal, Bhaina, Bhumia, Gond, Korku, Baiga, and Sahariya, etc. The districts where the scheluded tribes live are Balaghat, Mandia, Dindori, Chhindware, Shahdol, Sindhi, Jhabua, Anuppur, Khandwa, Shivpuri, Dhar and Khargon.

MP Board Solutions

MP Board Class 6th Social Science Miscellaneous Questions 3 Multiple Choice Questions 

Question 1.
The Shaka rulers made their capital?
(a) Delhi
(b) Ujjain
(c) Ajmer
(d) Bhopal
Answer:
(b) Ujjain

Question 2.
Who wrote “Harsha Charita”?
(a) Harsha vardhan
(b) Huen – Sang
(c) BanaBhatt
(d) Kalidasa
Answer:
(c) BanaBhatt

Question 3.
What was Bhukti?
(a) State
(b) District
(c) City
(d) Village
Answer:
(a) State

Question 4.
The painting in the caves of Bagh are the example of the paintings of which period?
(a) Kushana period
(b) Gupta period
(c) Harrappan period
(d) Vedic period
Answer:
(b) Gupta period

Question 5.
The senior most officer in a district is:
(a) District Superintendent of Police
(b) District Education Officer
(c) Collector
(d) District Project Officer
Answer:
(c) Collector

MP Board Solutions

Question 6.
The first iron and steel factory in India was established at:
(a) Bhilai
(b) Rourkela
(c) Vishakapattanam
(d) Kulti
Answer:
(a) Bhilai

Question 7.
The first cement factory in India was established in:
(a) Madhya Pradesh
(b) Bihar
(c) Uttar Pradesh
(d) Tamilnadu
Answer:
(d) Tamilnadu

Question 8.
The rank of India in production of coal is:
(a) first
(b) third
(c) fifth
(d) second
Answer:
(c) fifth

Question 9.
Which is harbour?
(a) Chennai
(b) Delhi
(c) Bhopal
(d) Mahabaleshwar
Answer:
(a) Chennai

Question 10.
The number of zones in the Indian Railways are:
(a) 7
(b) 8
(c) 9
(d) 10
Answer:
(c) 9

MP Board Solutions

Pick the odd one out:

  1. Kushana, Naga, Cher, Kanva.
  2. Meghdoot, Raghuvansha, Abhigyan Shakuntalam, Neetisar.
  3. Jawa, Yuvadweep, Indonesia, Burma.
  4. Chandragupta-I, Chandra Gupta-II, Raghvendra Gupta, Samudra Gupta.
  5. Gram Panchayat, Rajya Panchayat, Zila Panchayat, Nagar Panchayat.
  6. Sagaun, Sheesham, Coconut, Sal.
  7. Accacia, babul, water plant, cactii.
  8. Patato, sesame, mustard, groundnut.
  9. Chennai, Bhopal, Kolkata, Mumbai.

Answer:

  1. Chet
  2. Neetisaar
  3. Yavadweep
  4. Raghvendra Gupta
  5. Rajya Panchayat
  6. Coconut
  7. water plant
  8. sesame
  9. Bhopal

MP Board Solutions

Fill in the blanks:

  1. The last ruler of the Shung Dynesty was …………………..
  2. The Arch gate of Sanchi Stupa was built in the period of ………………………
  3. The title of Vikramaditya was given to ……………………
  4. The period of ……………….. is called the golden period.
  5.  ………………….. wrote Raghuvansha.
  6. The Chinese traveller Huen – Sang visited India in the period of ………………….
  7. Presently Nalanda is situated in the state of ………………….
  8.  ……………….. first translated the Buddhist books in Chinese.
  9. The founder of Christianity was …………………
  10. In the ancient times Iran was called …………………..

Answer:

  1. Brahdrath
  2. Satvahana
  3. Chandragupta – II
  4. Gupta
  5. Kalidasa
  6. Harsha
  7. Bihar
  8. Kashyap Matang
  9. Jesus
  10. Black Copper

MP Board Class 6th Social Science Solutions

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1

MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1

पाठ्य-पुस्तक पृष्ठ संख्या # 181-183

प्रश्न 1.
पाठ्य-पुस्तक में दिये गये चित्रों के लिए दी गई सारणी में संख्याएँ लिखिए
हल :
(a) पाठ्य-पुस्तक में 3 टॉवर हैं प्रत्येक में 10 इकाई हैं, 4 ब्लॉक हैं (1 इकाई) और 2 छोटे भाग (प्रत्येक दशांश के बराबर है)।
(b) पाठ्य-पुस्तक में 1 सैकड़ा, 1 दहाई, 0 इकाई और 4 दशांश हैं।
सारणी –
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 1

प्रश्न 2.
निम्न दशमलव संख्याओं को स्थानीय मान सारणी में लिखिए
(a) 19.4
(b) 0.3
(c) 10.6
(d) 205.9
हल:
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 2

प्रश्न 3.
निम्न में से प्रत्येक को दशमलव रूप में लिखिए
(a) 7 दशांश
(b) 2 दहाई, 9 दशांश
(c) चौदह दशमलव छः
(d) एक सौ और 2 इकाई
(e) छः सौ दशमलव आठ।
हल :
(a) 7 दशांश = 7 x \(\frac { 1 }{ 10 }\) = 0.7
(b) 2 दहाई, 9 दशांश = 2 x 10 + 9 x \(\frac { 1 }{ 10 }\)
= 20 + \(\frac { 9 }{ 10 }\)
= 20 + 0.9
= 20.9
(c) चौदह दशमलव छः = 14.6
(d)एक सौ और 2 इकाई = 1 सौ + 0 दहाई + 2 इकाई + 0 दशांश
= 100 + 0 + 2 + 0.0
= 102.0
(e) छः सौ दशमलव आठ = 600.8

MP Board Solutions

प्रश्न 4.
निम्न को दशमलव रूप में व्यक्त कीजिए
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 3a
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 3b
हल :
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 4

प्रश्न 5.
निम्न दशमलव संख्याओं को भिन्न के रूप में लिखकर न्यूनतम (सरलतम) रूप में बदलिए
(a) 0.6
(b) 2.5
(c) 1.0
(d) 3.8
(e) 13.7
(f) 21.2
(g) 6.4
हल :
(a) भिन्न = 0.6 = \(\frac { 6 }{ 10 }\)
सरलतम रूप = \(\frac{6 \div 2}{10 \div 2}=\frac{3}{5}\)

(b) भिन्न 2.5 = \(\frac { 25 }{ 10 }\)
सरलतम रूप = \(\frac{25 \div 5}{10 \div 5}=\frac{5}{2}\)

(c) भिन्न 1.0 = \(\frac { 10 }{ 10 }\) = 1
सरलतम रुप = \(\frac{10 \div 10}{10 \div 10}=\frac{1}{1}=1\)

(d) भिन्न = 3.8 = \(\frac { 38 }{ 10 }\)
सरलतम रूप = \(\frac{38 \div 2}{10 \div 2}=\frac{19}{5}\)

(e) भिन्न = 13.7 = \(\frac { 137 }{ 10 }\)
सरलतम रूप = \(\frac { 137 }{ 10 }\)

(f) भिन्न = 21.2 = \(\frac { 212 }{ 10 }\)
सरलतम रूप = \(\frac{212 \div 2}{10 \div 2}=\frac{106}{5}\)

(g) भिन्न = 6.4 = \(\frac { 64 }{ 10 }\)
सरलतम रूप = \(\frac{64 \div 2}{10 \div 2}=\frac{32}{5}\)

प्रश्न 6.
सेमी का प्रयोग कर निम्न को दशमलव रूप में बदलिए
(a) 2 मिमी
(b) 30 मिमी
(c) 116 मिमी
(d) 4 सेमी 2 मिमी
(e) 11 सेमी 52 मिमी
(f) 83 मिमी
हल :
(a) 2 मिमी = \(\frac { 2 }{ 10 }\) सेमी = 0.2 सेमी
(b) 30 मिमी = \(\frac { 30 }{ 10 }\) सेमी = 3.0 सेमी
(c) 116 मिमी = \(\frac { 116 }{ 10 }\) सेमी = 11.6 सेमी
(d) 4 सेमी 2 मिमी = 4 सेमी + \(\frac { 2 }{ 10 }\) सेमी
= 4 सेमी + 0.2 सेमी
= 4.2 सेमी
(e) 11 सेमी 52 मिमी = 11 सेमी + \(\frac { 52 }{ 10 }\) सेमी
= 11 सेमी + 5.2 सेमी
= 16.2 सेमी
(f) 83 मिमी = \(\frac { 80 }{ 10 }\) सेमी + \(\frac { 3 }{ 10 }\) सेमी
= 8 सेमी + 0.3 सेमी
= 8.3 सेमी

MP Board Solutions

प्रश्न 7.
संख्या रेखा पर किन दो पूर्ण संख्याओं के बीच निम्न संख्याएँ स्थित हैं ? इनमें से कौन-सी पूर्ण संख्या दी हुई दशमलव संख्या के अधिक निकट है ?
(a) 0.8
(b) 5.1
(c) 2.6
(d) 6.4
(e) 9.0
(f) 4.9
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 5
हल :
(a) 0.8 संख्या 0 और 1 के बीच में स्थित है और 1, 0.8 के अधिक निकट है।
(b) 5.1 संख्या 5 और 6 के बीच में स्थित है और 5, 5.1 के अधिक निकट है।
(c) 2.6 संख्या 2 और 3 के बीच में स्थित है और 3, 2.6 के अधिक निकट है।
(d) 6.4 संख्या 6 और 7 के बीच में स्थित है और 6, 6.4 के अधिक निकट है।
(e) 9.0 स्वयं 9 पूर्ण संख्या है।
(f) 4.9 संख्या 4 और 5 के बीच में स्थित है और 5, – 4.9 के अधिक निकट है।

प्रश्न 8.
निम्न को संख्या रेखा पर दर्शाओ
(a) 0.2
(b) 1.9
(c) 1.1
(d) 2.5
हल :
संख्या रेखा
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 6

प्रश्न 9.
दी हुई संख्या रेखा स्थित A, B, C, D बिन्दुओं के लिए दशमलव संख्या लिखिए
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 7
हल :
A → 0.8,
B → 1.3,
C → 2.2,
D → 2.9.

प्रश्न 10.
(a) रमेश की कॉपी की लम्बाई 9 सेमी 5 मिमी है। सेमी में इसकी लम्बाई क्या होगी?
(b) चने के एक छोटे पौधे की लम्बाई 65 मिमी है। इसकी लम्बाई सेमी में व्यक्त कीजिए।
हल :
(a) रमेश की कॉपी की लम्बाई
= 9 सेमी 5 मिमी
= 9 सेमी + \(\frac { 5 }{ 10 }\) सेमी
= 9 सेमी + 0.5 सेमी
= 9.5 सेमी
अतः रमेश की कॉपी की लम्बाई = 9.5 सेमी

(b) चने के पौधे की लम्बाई = 65 मिमी = \(\frac { 65 }{ 10 }\) सेमी
= \(\frac { 60 }{ 10 }\) सेमी + \(\frac { 5 }{ 10 }\) सेमी
= 6.5 सेमी
अतः चने के पौधे की लम्बाई = 6.5 सेमी।

MP Board Solutions

पाठ्य-पुस्तक पृष्ठ संख्या # 183

प्रश्न 1.
पाठ्य-पुस्तक में पृष्ठ संख्या 184 पर दी गई आकृतियों में यदि हम बड़े वर्ग के 8 वर्ग छायांकित करें, 15 वर्ग छायांकित करें, 50 वर्ग छायांकित करें, 92 वर्ग छायांकित करें तो वह पूरे वर्ग का कौन-सा भाग होगा ?
हल :
MP Board Class 6th Maths Solutions Chapter 8 दशमलव Ex 8.1 image 8

MP Board Class 6th Maths Solutions

MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.3

MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.3

पाठ्य-पुस्तक पृष्ठ संख्या # 143

प्रश्न 1.
घटाइए:
(a) 35 – (20)
(b) 72 – (90)
(c) ( – 15) – ( – 18)
(d) ( – 20) – (13)
(e) 23 – ( – 12)
(f) ( – 32) – ( – 40)
हल :
(a) 35 – (20)
= 15 + 20 – 20
= 15 + 0
= 15

(b) 72 – (90)
= 72 – (72 + 18)
= 72 – 72 – 18
= 0 – 18
= – 18

(c) ( – 15) – ( – 18)
= ( – 15) + (योज्य प्रतिलोम – 18)
= – 15 + 18
= – 15 + (15 + 3)
= – 15 + 15 + 3
= 0 + 3
= 3

(d) ( – 20) – (13)
= – 20 – 13
= – (20 + 13)
= – 33

(e) 23 – ( – 12)
= 23 + 12
= 35

(f) ( – 32) – ( – 40)
= – 32 + 40
= – 32 + (32 + 8)
= 32 + 32 + 8
= 0 + 8
= 8

प्रश्न 2.
रिक्त स्थानों को >, < या = से भरिए
हल :
(a) ( – 3) + ( – 6) < ( – 3) – ( – 6)
(b) ( – 21) – ( – 10) > ( – 31) + ( – 11)
(c) 45 – ( – 11) > 57 + ( – 4)
(d) ( – 25) – ( – 42) > ( – 42) – ( – 25)

MP Board Solutions

प्रश्न 3.
रिक्त स्थानों को भरिए
(a) ( – 8)+ …. = 0
(b) 13 + …. = 0
(c) 12 + ( – 12) = …..
(d) ( – 4)+ …. = -12
(e) …. – 15 = – 10
हल :
(a) 8,
(b) – 13,
(c) 0,
(d) – 8,
(e) 5.

प्रश्न 4.
निम्नलिखित के मान ज्ञात कीजिए
(a) ( – 7) – 8 – ( – 25)
(b) ( – 13) + 32 – 8 – 1
(c) ( – 7) + ( – 8) + ( – 90)
(d) 50 – ( – 40) – ( – 2)
हल :
(a) ( – 7) – 8 – ( – 25)
= ( – 7) + ( – 8) + 25
= – 15 + 15 + 10
= 0 + 10
= 10

(b) ( – 13) + 32 – 8 – 1
= ( – 13) + 32 + ( – 8) + ( – 1)
= – (13 + 8 + 1) + 32
= – 22 + 32
= – 22 + 22 + 10
= 0 + 10
= 10

(c) ( – 7) + ( – 8) + ( – 90)
= – 7 – 8 – 90
= – 105

(d) 50 – ( – 40) – ( -2)
= 50 + ( + 40) + (+ 2)
= 50 + 40 + 2
= 92

MP Board Class 6th Maths Solutions

MP Board Class 6th Social Science Solutions Chapter 27 The Means of Transport in India

MP Board Class 6th Social Science Solutions Chapter 27 The Means of Transport in India

MP Board Class 6th Social Science Text Book Exercise Questions

Answer the following questions:

Question (a)
What are means of transport? Give two examples.
Answer:
All the means used for moving from one place to another are called the means of transport.
Examples: Bus, railway, aeroplane, etc.

Question (b)
Write the names of the main means of transport in India.
Answer:
The means of transport makes important contribution in linking far off places, social integrity and unity and defence of the country. Different means of transport move on different routes.
Example: cycle, bullock cart, buses and car moves on road; trains move on railway tracks aeroplane move in air and boats, ships move on water.

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Question (c)
State the difference between National and State Highways.
National Highways:

  1. National Highways join capital and the main cities of the country and extend upto the territorial boundaries of our country.
  2. These roads are managed and looked after by the Central Government.
  3. Grand Trunk Road (G.T. Road) are the National Highways.

State Highways:

  1. State Highways join main districts cities with the national highways. These roads limit upto the state boundaries only.
  2. These roads are looked after by the state Governments.
  3. Roads connecting two cities in a state are examples of State Highways.

Question (d)
Which National Highway connects Jabalpur and Jaipur.
Answer:
National Highway 3 connects Jabalpur and Jaipur.

Question (e)
Into how many zones have the Indian Railways been divided? Name them.
Answer:
The railways in India has been divided into nine zones for proper management. They are:

  1. Eastern Railway
  2. Northern Railway
  3. Southern Railway
  4. Central Railway
  5. North – East Frontier Railway
  6. South Central Railway
  7. South – Eastern Railway
  8. Western Railway
  9. North – Eastern Railway

MP Board Solutions

Question (f)
Which countries are connected by water transport from Mumbai and Kolkata harbours?
Answer:
Karachi, Captown, Africa are connected by water transport from Mumbai and Yangun is connected by water transport from Koikata.

Question (g)
Name any four harbours of India.
Answer:
The four harbours of India are Kandla, Mumbai, Chennai and Kolkata.

Question (h)
Why are the rivers of Southern India not appropriate for internal transport through water?
Answer:
The rivers of Southern India flow on the hilly areas of the plateau which have much ups and downs. Therefore, they are not appropriate for water transport.

MP Board Solutions

Question 2.
Mark the following in the given map:

  1. National Highway No. 3 and 6.
  2. Mumbai – Chennai rail route
  3. Water route through Vishakhapatanam.
  4. Water route through Paradip.
  5. Delhi – Chennai air – route.
  6. Kolkata Harbour.

Answer:
Do yourself.

MP Board Class 6th Social Science Solutions

MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2

MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2

पाठ्य-पुस्तक पृष्ठ संख्या # 140-141

प्रश्न 1.
संख्या रेखा का प्रयोग करते हुए, वह पूर्णांक ज्ञात कीजिए जो :
(a) 5 से 3 अधिक है
(b) – 5 से 5 अधिक है
(c) 2 से 6 कम है
(d) – 2 से 3 कम है।
हल :
(a) 5 से 3 अधिक है
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 1
हम 5 से प्रारम्भ करते हुए दाईं ओर 3 कदम चलते हैं तथा .8 प्राप्त करते हैं। अत: 5 से 3 अधिक 8 है।

(b)-5 से 5 अधिक है
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 2
हम – 5 से प्रारम्भ करते हुए दाईं ओर 5 कदम चलते हुए 0 प्राप्त करते हैं। अतः-5 से 5 अधिक 0 है।

(c) 2 से 6 कम है
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 3
हम 2 से प्रारम्भ करते हुए बाईं ओर 6 कदम चलते हैं तथा – 4 प्राप्त करते हैं। अतः 2 से 6 कम – 4 है।

(d) -2 से 3 कम है ।
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 4
हम – 2 से प्रारम्भ करते हुए बाईं ओर 3 कदम चलते हैं तथा – 5 प्राप्त करते हैं। अत: – 2 से 3 कम – 5 है।

प्रश्न 2.
संख्या रेखा का प्रयोग करते हुए निम्नलिखित योग ज्ञात कीजिए :
(a) 9 + (-6)
(b) 5 + (-11)
(c) (-1) + (-7)
(d) (-5) + 10
(e) (-1) + (-2) + (-3)
(f) (-2) + 8 + (-4)
हल :
(a) 9 + (-6)
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 5
सर्वप्रथम हम संख्या रेखा पर 0 के दाईं ओर 9 कदम चलकर 9 पर पहुँचते हैं। फिर 9 के बाईं ओर 6 कदम चलकर 3 पर पहुँचते हैं।
अतः 9+ (-6) = 3

(b) 5 + (-11)
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 6
संख्या रेखा पर पहले 0 से दाईं ओर 5 कदम चलते हैं और 5 पर पहुँचते हैं। फिर 5 के बाईं ओर 11 कदम चलते हैं तथा – 6 पर पहुँचते हैं।
अतः 5 + (-11) = – 6

(c) (-1) + (-7)
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 7
संख्या रेखा पर पहले 0 के बाईं ओर 1 कदम चलते हैं और – 1 पर पहुँचते हैं। फिर – 1 के बाईं ओर 7 कदम चलते हैं तथा – 8 पर पहुँचते हैं।
अतः (-1) + (-7) = -8

(d) (-5) + 10
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 8
संख्या रेखा पर पहले 0 के बाईं ओर 5 कदम चलते हैं और – 5 पर पहुँचते हैं। फिर – 5 के दाईं ओर 10 कदम चलते हैं तथा 5 पर पहुँचते हैं। अतः (-5) +10 = 5

(e) (-1) + (-2) + (-3)
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 9
हम संख्या रेखा पर (0 के बाईं ओर 1 कदम चलते हैं और – 1 पर पहुँचते हैं। फिर – 1 के बाईं ओर 2 कदम चलते हैं और – 3 पर पहुँचते हैं। पुन: -3 के बाईं ओर 3 कदम चलते हैं तथा – 6 पर पहुँचते हैं।
अतः (-1) + (-2) + (-3) = – 6

(f) (-2) + 8 + (-4)
MP Board Class 6th Maths Solutions Chapter 6 पूर्णांक Ex 6.2 image 10
हम संख्या रेखा पर 0 के बाईं ओर 2 कदम चलते हैं और -2 पर पहुँचते हैं। फिर – 2 से दाईं ओर 8 कदम चलते हैं और 6 पर पहुँचते हैं। पुन: 6 के बाईं ओर 4 कदम चलते हैं तथा 2 पर पहुँचते हैं। अतः (-2) + 8 + (-4) = 2

MP Board Solutions

प्रश्न 3.
संख्या रेखा का प्रयोग किए बिना, निम्नलिखित योग ज्ञात कीजिए
(a) 11 + (-7)
(b) (-13) + (+ 18)
(c) (-10) + (+ 19)
(d) (-250) + (+ 150)
(e) (-380) + (-270)
(f) (-217) + (-100)
हल :
(a) 11 + (-7)
= 4 + 7 + (-7)
= 4 + 0
= 4

(b) (-13) + (+ 18)
= (- 13) + (+ 13) + (+5)
= 0 + (+ 5)
= 5

(c) (-10) + (+ 19)
= (- 10) + (+ 10) + (+ 9)
= 0 + (+ 9)
= 9

(d) (-250) + (+ 150)
= (- 100) + (- 150) + (+ 150)
= (- 100) + 0
= – 100

(e) (-380) + (-270)
= – (380 + 270)
= -650

(f) (-217) + (-100)
= – (217 + 100)
= – 317

प्रश्न 4.
निम्नलिखित का योग ज्ञात कीजिए :
(a) 137 और – 354
(b) – 52 और 52
(c) – 312, 39 और 192
(d) – 50, – 200 और 300
हल :
(a) (+ 137) + (-354)
= (+ 137) + (- 137) + (- 217)
= 0 + (-217)
= – 217

(b) (-52) + (+ 52)= 0

(c)(-312) + (+ 39) + (192)
= (-312) + (+ 231)
= (-81) + (-231) + (+ 231)
= (-81) + 0
= -81

(d) (-50) + (-200) + (+ 300)
= (-250) + (+ 300)
= (-250) + (+ 250) + (+ 50)
= 0 + (+ 50)
= 50

MP Board Solutions

प्रश्न 5.
निम्नलिखित के मान ज्ञात कीजिए
(a) (-7) + (-9) + 4 + 16
(b) (37) + (-2) + (-65) + (-8)
हल :
(a) (-7) + (-9) + 4 + 16
= (- 16) + 4 + 16
= (- 16) + 16 + 4
= 0 + 4
= 4

(b) (37) + (-2) + (-65) + (-8)
= 37 + (-75)
= 37 + (-37) + (-38)
= 0 + (-38)
= – 38

MP Board Class 6th Maths Solutions

MP Board Class 6th Social Science Solutions Chapter 17 The Climate of India

MP Board Class 6th Social Science Solutions Chapter 17 The Climate of India

MP Board Class 6th Social Science Chapter 17 Text Book Exercise

MP Board Class 6th Social Science Chapter 17 Short Answer Type Questions

Question 1.
Question (a)
What is Monsoon?
Answer:
The word ‘Monsoon’ originates from an Arabic word ‘Mausim’ meaning season. India is situated in the tropical zone. Most of our rain is brought by the monsoon winds. Our farmers depend very much on the monsoon showers to assure a good harvest. If monsoon comes early the crops suffer because fields are not ready to receive the rain. If it delays it causes drought. Thus, climatically monsoon is a very Important phenomenon.

Question (b)
What is retreating monsoon?
Answer:
Retreating monsoon winds begin to withdraw from land. The period from 2nd week of September to November is the period of retreating monsoon. They do not cause any rains over most parts of the country except the eastern coast of India and the Tamil Nadu coasts. Retreating monsoon winds after passing over the Bay of Bengal cause rains on the Orissa, Andhra Pradesh and Tamil Nadu coasts.

MP Board Solutions

Question (c)
What is temperature variation?
Answer:
The temperature variation is more in North India than in the South India.

Question (d)
What is the climate of India called?
Answer:
The climate of India is called monsoon climate.

Question (e)
What are the four seasons is India?
Answer:
The four seasons in India are:

  1. Cold weather season (winter)
  2. Hot weather season (summer)
  3. Advancing monsoon season (rainy)
  4. Season of retreating monsoon (autumn)

Question (f)
Explain the general condition in winter in India?
Answer:
The temperature is low in northern India and atmospheric pressure is high. Winds blow from high pressure belt to low pressure belt, i.e from land to sea. Since the winds blow from the land, they are dry and cold. Their direction is north – east to south – west. Temperature falls rapidly. The characteristics of the winter seasons are:

  1. Cold waves blow in all parts of northern India.
  2. The western cyclone causes a little rainfall in the north – west.
  3. The monsoon winds coming back from the Bay of Bengal causes rainfall in the coast of Tamil Nadu.

MP Board Solutions

Question 2.
Fill in the blanks:

  1. In the north – west rainfall is caused by …………….. in winter.
  2. When temperature rises, atmospheric pressure became …………………
  3. The hot wind that blows in north west of India in summer in the afternoon is called ………………..
  4. When temperature falls down 5° celcius, the cold wind that blows, is called ……………….

Answer:

  1. western cyclone
  2. low
  3. loo
  4. cold wave.

MP Board Class 6th Social Science Chapter 17 Long Answer Type Questions

Question 3.
Question (a)
What are the factors that effect the climate of India ? Describe in detail?
Answer:
The following factors affect the climate of India:

1. Geographical position:
India is located between 8°4’N to 37°6’N latitude. The Tropic of Cancer divides it into almost two equal parts. Indian ocean stretches in the south of India. There are high mountains of the Himalayas in the North. The winds get enough moisture as it is surrounded by water on three sides.

2. The form of the surface of the earth:
The Himalayas stretches like a wall from east to west. It stops the cold winds blowing from the North pole and saves India from severe cold. On the other land it also stops the moist monsoon winds and causes rainfall.

3. Winds:
If the winds did not change direction with the change of season, India would have been a dry desert. In the north, change in the atmospheric pressure in Asia also changes the direction of the winds.

Question (b)
What are the characteristics of the Indian climate?
Answer:
The main characteristics of the Indian climate are:

  1. Climate of India is Monsoon climate.
  2. Most of the raimail occur in four months from June to September.
  3. The temperature variation is more in North India than in the South India.
  4. The distribution of rainfall is uneven.
  5. The climate affects the life of the people.
  6. The inner parts of India have continental and the coastal parts have moderate climate.
  7. Cyclones occur before and after Monsoon. They cause rain.

MP Board Solutions

Question (c)
How does Monsoon originate in India?
Answer:
The period from June to September is the south – west monsoon season. The low pressure area developed in the north – west of the sub – continent becomes intense. The south east trade winds blow towards low pressure area in the North India. These moist winds enter into the two oceans on the east as well as on the west (Bay of Bengal and the Arabian Sea). Suddenly they are caught up in the circulation over India and bring rain. The whole country, at one time or the other, gets rain in about 4 to 5 months either through south – west monsoon or north – east monsoon.

Question 4.
Show the following in the map of India:
Tropic of Cancer, Cherapunji and summer winds areas with heavy rain, Arabian sea, Bay of Bengal, Indian Desert?
Answer:
Do yourself.
MP Board Class 6th Social Science Solutions Chapter 17 The Climate of India img 1
Question 5.
Look at the map above and say?

  1. In which direction are the winds blowing in the south?
  2. Are the winds blowing from land to sea or sea to land?
  3. Would the winds cause rainfall?

Answer:

  1. Winds are blowing from high pressure belt to low pressure belt.
  2. Winds are blowing from sea (Indian Ocean) to land (Indian Peninsula).
  3. Yes.

MP Board Class 6th Social Science Solutions

MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5

MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5

पाठ्य-पुस्तक पृष्ठ संख्या # 171-172

प्रश्न 1.
निम्न भिन्नों को योग या घटाने के उचित रूप में लिखिए
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 1
हल :
(a) +,
(b) -,
(c) +

प्रश्न 2.
हल कीजिए
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 2
हल :
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 3
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5

MP Board Solutions

प्रश्न 3.
शुभम ने अपने कमरे की दीवार के \(\frac { 2 }{ 3 }\) भाग पर पेंट किया। उसकी बहन माधवी ने उसकी सहायता की और उस दीवार के \(\frac { 1 }{ 3 }\) भाग पर पेंट किया। उन दोनों ने मिलकर कुल कितना पेंट किया ?
हल :
शुभम द्वारा पेण्ट किया दीवार का भाग = \(\frac { 2 }{ 3 }\)
माधवी द्वारा पेण्ट किया गया दीवार का भाग = \(\frac { 1 }{ 3 }\)
दोनों द्वारा पेण्ट की गई दीवार
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 4
अत: दोनों ने मिलकर पूरी दीवार पेंट की।

प्रश्न 4.
रिक्त स्थानों को भरिए
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 5
हल :
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 6

प्रश्न 5.
जावेद को सन्तरों की एक टोकरी का \(\frac { 5 }{ 7 }\) भाग मिला। टोकरी में सन्तरों का कितना भाग शेष रहा ?
हल :
माना कि सन्तरों की पूरी टोकरी = 1
जावेद को मिला सन्तरों का भाग = \(\frac { 5 }{ 7 }\)
टोकरी में बचे सन्तरों का भाग
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 7
अतः टोकरी में सन्तरों का \(\frac { 2 }{ 7 }\) भाग शेष रहा।

MP Board Solutions

पाठ्य-पुस्तक पृष्ठ संख्या # 173

प्रयास कीजिए

प्रश्न 1.
\(\frac { 2 }{ 5 }\) और \(\frac { 3 }{ 7 }\) को जोड़िए।
हल :
\(\frac { 2 }{ 5 }\) और \(\frac { 3 }{ 7 }\)
∵ 5 और 7 का ल.स. = 35.
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 8

प्रश्न 2.
\(\frac { 5 }{ 7 }\) में से \(\frac { 2 }{ 5 }\) को घटाइए।
हल :
\(\frac{5}{7}-\frac{2}{5}\)
∵ 7 और 5 का ल. स. = 35
MP Board Class 6th Maths Solutions Chapter 7 भिन्न Ex 7.5 image 9

MP Board Class 6th Maths Solutions