## MP Board Class 7th Maths Solutions Chapter 4 Simple Equations Ex 4.3

**Class 7 Maths Chapter 4 Exercise 4.3 Solutions Question 1.**

Solve the following equations:

(a) \(2 y+\frac{5}{2}=\frac{37}{2}\)

(b) 5t + 28 = 10

(c) \(\frac{a}{5}+3\) = 2

(d) \(\frac{q}{4}+7\) = 5

(e) \(\frac{5}{2} x\) = -10

(f) \(\frac{5}{2} x=\frac{25}{4}\)

(g) \(7 m+\frac{19}{2}\) = 13

(h) 6z + 10 = -2

(i) \(\frac{3 l}{2}=\frac{2}{3}\)

(j) \(\frac{2 b}{3}-5\) = 3

Solution:

**Class 7th Maths Chapter 4 Exercise 4.3 Question 2.**

Solve the following equations.

(a) 2(x + 4) = 12

(b) 3(n – 5) = 21

(c) 3(n – 5) = -21

(d) -4(2 + x) = 8

(e) 4(2 – x) = 8

Solution:

(a) 2(x + 4) = 12

Dividing both sides by 2,

(Transposing 4 to R.H.S.)

(b) 3(n – 5) = 21

Dividing both sides by 3,

(Transposing – 5 to R.H.S.)

(c) 3(n – 5) = -21

Dividing both sides by 3,

(Transposing – 5 to R.H.S.)

(d) – 4(2 + x) = 8

Dividing both sides by – 4,

(Transposing 2 to R.H.S.)

(e) 4(2 – x) = 8

Dividing both sides by 4,

(Transposing 2 to R.H.S.)

⇒ x = 0

**Class 7 Maths Chapter 4 Exercise 4.3 Question 1 Question 3.**

Solve the following equations:

(a) 4 = 5(p – 2)

(b) -4 = 5(p – 2)

(c) 16 = 4 + 3(t + 2)

(d) 4 + 5(p – 1) = 34

(e) 0 = 16 + 4(m – 6)

Solution:

(a) 4 = 5(p – 2)

Dividing both sides by 5,

**Class 7 Maths Chapter 4 Exercise 4.3 Question 4.**

(a) Construct 3 equations starting with x= 2.

(b) Construct 3 equations starting with x = -2.

Solution:

(a) x = 2

Multiplying both sides by 5,

5x = 10 … (i)

(b) Let the number be x.

Subtracting 3 from both sides,

5x – 3 = 10 – 3

5x – 3 = 7 …(ii)

Dividing both sides by 2,

(b) x= -2

Subtracting 2 from both sides,

x – 2 = -2 – 2 ⇒ x – 2 = -4 … (i)

Again, take x = – 2

Multiplying both sides by 6,

6 × x = -2 × 6 ⇒ 6x = -12

Subtracting 12 from both sides,

6x – 12 = – 12 – 12 ⇒ 6x – 12 = – 24 …(ii)

Adding 24 to both sides,

6x – 12 + 24 = – 24 + 24

⇒ 6x + 12 = 0 …(iii)