MP Board Class 9th English Solutions The Rainbow, The Spring Blossom

MP Board Class 9th English Solutions Guide Pdf Free Download of Text Books The Rainbow, The Spring Blossom Questions and Answers, Notes, Summary are part of MP Board Class 9th Solutions. Here we have given Madhya Pradesh Syllabus MP Board Class 9 English Book Solutions Pdf of The Rainbow, The Spring Blossom Textbook Workbook Special, and General English Class 9th Solutions.

MP Board Class 9th English Book Solutions

FREE downloadable MP Board Class 9th Special English The Rainbow Text Book, Workbook Solutions and MP Board Class 9th General English The Spring Blossom Text Book, Workbook Solutions and Answers, Check MP Scholarship here.

The Rainbow Textbook Special English Class 9th Solutions

You can download MP Board The Rainbow Textbook Special English Class 9th Solutions, Questions and Answers, Notes, Summary, Lessons: Pronunciation, Translation, Word Meanings, Textual Exercises.

The Rainbow Workbook Special English Class 9th Solutions

You can download MP Board The Rainbow Workbook Special English Class 9th Solutions and Answers.

MP Board Class 9th Special English Reading Skills

MP Board Class 9th Special English Reading Unseen Passages

MP Board Class 9th Special English Writing Skills

MP Board Class 9th Special English Grammar

The Spring Blossom Textbook General English Class 9th Solutions

You can download MP Board The Spring Blossom Textbook General English Class 9th Solutions, Questions and Answers, Notes, Summary, Lessons: Pronunciation, Translation, Word Meanings, Textual Exercises.

Objective Type Questions [Based on Textual Lessons]

MP Board Class 9th General English Reading Skills

MP Board Class 9th General English Reading Unseen Passages

MP Board Class 9th General English Writing Skills

MP Board Class 9th General English Grammar

MP Board Class 9th Special English Syllabus & Marking Scheme

Time: 3.00 Hours
Maximum Marks: 100

Unit Wise Weightage

Section Topics Marks
A Reading Skills (Reading Unseen Passages) 30
B Writing Skills 30
C Grammar 15
D Prescribed Text Book 25
Total 100

Examination Specifications
Class – IX

On Paper 3 Hours
100 Marks

Section A: Reading (30 Marks, 54 Periods)

Three unseen passages with a variety of comprehension questions including 05 marks for word attach skill such as word formation and inferring meaning.

  • About 200 words in length (8 Marks)
  • About 200 words in length (8 Marks)
  • About 300 words in length (14 Marks)

The total length of the three passages will be between 600 and 700 words.
The passages will include one of each of the following types.
Factual passage, e.g. instruction, description, report.
Discursive passage involving opinion e.g. argumentative, persuasive or interpretative text.
Literary passage, e.g. extract from fiction, drama, poetry, essay or biography
In the case of Poetry extract, the text may be shorter than 150 words.

Section B: Writing (30 Marks, 54 Periods)

Four Writing Tasks indicated below:

  1. Controlled tasks where a student builds up a short composition with guidance. (5 Marks)
  2. Short composition of not more than 50 words, e.g. a not, notice, message, telegram or short postcard. (5 marks.)
  3. Composition in response to some verbal stimulus such as an advertisement, a notice, a newspaper clipping, a table, a diary extract notes, letter or other forms of correspondence. (10 Marks)
  4. Composition response to some visual stimulus such as a diagram, a picture, a graph, a map, a cartoon or a flow chart. (10 Marks)

One of the longer (10 marks) compositions will draw on the thematic content of the Main Course Book.
At least one task will involve, the productions of a form of correspondence, e.g. a letter, postcard, note or notice.
One task will involve the production of a discursive text in which the student is required to express his/her point of view on the topic given.

Section C: Grammar (15 marks)

A variety of short questions involving the use of particular structures within a context (i.e. not in isolated sentences) Test types used will include, for example, gap-filling, cloze (gap filling exercise with blanks at regular intervals) sentence completion, sentence-reordering, editing, dialogue, Completion and sentence transformation.
Not all elements in the grammar syllabus can be included in the questions paper every year.
However, questions will be distributed over the following three broad areas: verb forms, sentences, structures and others.

Section D: Literature (25 Marks, 45 Periods)

  1. Two extracts from different poems from the prescribed reader, each followed by two or three questions to test local and global comprehension of the set text. Each extract will carry 4 marks. (8 Marks)
  2. One or two questions based on one of the drama texts from the prescribed reader to test local and global comprehension of the set text. An extract may or may not be used. (8 Marks)
  3. One question based on one of the prose texts from the prescribed reader to test global comprehension and extrapolation beyond the set text. (4 Marks)
  4. Extended questions based on one of the prose texts from the prescribed reader to test global comprehension and extrapolation beyond the set text. (8 Marks)
    Questions will test comprehension at different levels: literal inferential and evaluative.

Final Examination

This is a formal three-hour examination held at the end of Class IX and carries 100% marks. It tests all the reading and writing skills specified in the teaching/testing objectives, together with a representative sample of the Literature and Grammer objectives.

Book Prescribed:

  1. Text Book The Rainbow with Supplementary Material.
  2. Work Book The Rainbow

Compiled by M.P. Rajya Shiksha Kendra and Published by M.P. Text Book Corporation. Bhopal.

MP Board Class 9th General English Syllabus & Marking Scheme

Time: 3.00 Hours
Maximum Marks = 100

Unit wise Weightage

Section Topics Marks Time
A Reading Skills Reading and Comprehension 15 27 Periods
B Writing Skills 20 36 Periods
C Grammar 20 36 Periods
D Prescribed Text Book 45 81 Periods

Examination Specifications

Section A: Reading (15 Marks)

A1, A2 and A3 three unseen passages of total 250 words with a variety of questions including 6 marks for vocabulary.
The prose passage will be factual (instructions, description, report etc), discursive (argumentative, interpretative, persuasive, etc) and literary (poetry, fiction, interview, biography, etc) in nature.

  • Passage 1. 80 words (5 marks)
  • Passage 2. 80 words (5 marks)
  • Passage 3. 80 words (5 marks)

There will be questions for local comprehension besides questions on vocabulary and comprehension of higher-level skills such as drawing inferences and conclusions.

Section B: Writing (20 Marks)

B1. Letter writing: One letter based on provided verbal stimulus and context. (6 Marks)
Type of Letter: informal: personal such as to family and friends
Formal: letters of complaints, enquiries, requests, applications.

B2. Note making and summarising: (6 Marks)

  • Students will be asked to make notes on the passage given (100 words) (3 Marks)
  • The students will be asked to prepare a summary looking at the given notes. (3 Marks)

B3. Composition: A short writing task based on a verbal and/or visual stimulus (diagram, picture, graph, map, chart, table, flow chart etc) (80 words) (8 Marks)
OR
An essay in about 200 words on topics of day to day life.
After giving an example practice to students to write an original composition for two or three years, the option of ‘Essay’ may be eliminated.

Section C: Grammar and Translation (20 Marks)

A variety of short questions involving the use of particular structures within a context. Test Types used will include clauses, gap-filling, sentence completion, sentence re-ordering, editing, dialogue-completion and sentence transformation. The Grammar syllabus for this class will include the following areas for teaching.

1. Tenses (present with extension);
2. Modals (have to/had to, must, should, need, ought to and their negative forms);
3. Use of passive voice;
4. Subject-verb concord;
5. Reporting; (i) Commands and requests, (ii) Statements, (iii) Questions
6. Clauses: (i) Noun-clauses (ii) Adverb clauses of condition and time (iii) Relative clauses;
7. Determiners, and
8. Prepositions
9. Translation (from Hindi to English)
Note: No separate marks allotted for any of grammatical items listed above.

4. Section D: Text Book (45 Marks)

Prose 30 (Marks)

D.1 and D.2 – Two extracts from different prose lessons included in Text Book (approximately 100 words each) (5 × 2 = 10 Marks)
These extract chosen from different lessons will be literary and discursive in nature. Each extract will be of 5 marks. One mark in each extract will be for vocabulary. 4 marks in each passage will be used for testing local and global comprehension besides a question on interpretation.

D.3. One out of two questions: based on any one of the prose lesson from the textbook to be answered in about 50 to 80 words. (6 Marks)

D.4 (A) One out of two questions on drama text (local and global comprehension questions) (50-80 words) (6 Marks)
(B) One out of two questions on drama text in (25-30 words) (4 Marks)

D.5. Four objective type question based on Text. (4 Marks)

Poetry (15 Marks)

D.6. One out of two extracts from different poems from the prescribed reader, each followed by two or three questions to test the local and global comprehension of the set text. (3 Marks)

D.7. Two out of three short answer type questions on substance and ideas contained in the poems to be answered in about 20-25 words each. (6 Marks)

D.8. One out of two short answer type questions central idea of the poems. (4 Marks)

D.9. Objective text based on poetry. (2 Marks)

Book Prescribed:

  1. Text Book – Spring Blossom
  2. WorkBook – Spring Blossom

Compiled by M.P. Rajya Shiksha Kendra and Published by M.P. Text Book Corporation.

MP Board Class 9 Special English Blue Print of Question Paper

You can download MP Board Class 9th English Blueprint and Marking Scheme 2019-2020 in Hindi and English medium.

MP Board Class 9 English Blue Print of Question Paper 3
MP Board Class 9 English Blue Print of Question Paper 4

MP Board Class 9 General English Blue Print of Question Paper

MP Board Class 9 English Blue Print of Question Paper 1MP Board Class 9 English Blue Print of Question Paper 2

MP Board Class 9 Special English Format of Question Paper Design

MP Board Class 9 English Format of Question Paper 3
MP Board Class 9 English Format of Question Paper 4

MP Board Class 9 General English Format of Question Paper Design

MP Board Class 9 English Format of Question Paper 1
MP Board Class 9 English Format of Question Paper 2

We hope the given MP Board Class 9th English Solutions Guide Pdf Free Download of Books The Rainbow, The Spring Blossom Solutions, Questions and Answers, Notes, Summary will help you. If you have any queries regarding Madhya Pradesh Syllabus MP Board Class 9 English Book Solutions Pdf of The Rainbow, The Spring Blossom Textbook Workbook Special and General English Class 9th Solutions, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Social Science Solutions सामाजिक विज्ञान

MP Board Class 9th Social Science Solutions Guide Pdf Free Download सामाजिक विज्ञान in both Hindi Medium and English Medium are part of MP Board Class 9th Solutions. Here we have given Madhya Pradesh Syllabus MP Board Class 9 Social Science Book Solutions Samajik Vigyan Pdf.

MP Board Class 9th Social Science Book Solutions in Hindi Medium

Social Science Class 9 MP Board Book Solutions Geography भूगोल

Social Science Class 9 MP Board Guide History इतिहास

MP Board 9th Class Social Science Book Solutions Civics नागरिकशास्त्र

MP Board Social Science Book Class 9 Economics अर्थशास्त्र

MP Board Class 9th Social Science Book Solutions in English Medium

MP Board 9th Social Science Book Pdf In English Geography Solutions

MP Board Class 9th Social Science Solution History Solutions

Class 9 Social Science MP Board Civics Solutions

MP Board 9th Class Social Science Book Economics Solutions

MP Board Class 9th Social Science Syllabus

इकाई 1: पर्यावरण (8 Marks)
पर्यावरण की भारतीय अवधारणा, प्राकृतिक एवं सांस्कृतिक पर्यावरण। मानव एवं पर्यावरण का सम्बन्ध तथा प्रभाव। पर्यावरण प्रदूषण के प्रकार, प्रभाव एवं निराकरण के उपाय। भूमि के बदलते उपयोगों के कारण पारिस्थितिक तन्त्र का क्षरण, इसके लिए जिम्मेदार कारण, जैसे—जनसंख्या वृद्धि, औद्योगीकरण एवं शहरीकरण, यातायात, जलीय स्थलों पर अतिक्रमण, पर्यटन हेतु सुविधाएँ, धार्मिक तीर्थ-स्थल, मनोरंजन एवं साहसिक कार्यों हेतु भूमि उपयोग, बड़े बाँधों का निर्माण, खनन एवं युद्ध। प्राकृतिक पर्यावरण के संसाधन, दोहन एवं संरक्षण।
पर्यावरण संरक्षण सम्बन्धी सफलता की कुछ कहानियाँ, जैसे-
सी.एन.जी., चिपको आन्दोलन, साइलेण्ट वैली, वाटर हार्वेस्टिंग। पर्यावरणीय प्रभाव अध्ययन (EIA) की भूमिका।

इकाई 2: भारत-स्थिति, प्राकृतिक विभाग (4 Marks)
भारत की भौगोलिक स्थिति, प्राकृतिक विभाग

इकाई 3: जलवायु एवं अपवाह तंत्र (4 Marks)
जलवायु को प्रभावित करने वाले कारक, मानसून और उसकी विशेषताएँ, वर्षा व तापमान का वितरण। मौसम तथा जलवायु का मानव जीवन पर प्रभाव। मुख्य एवं सहायक नदियाँ, झीलें एवं समुद्र, देश की अर्थव्यवस्था में नदियों की भूमिका। नदी प्रदूषण एवं नियन्त्रण के उपाय।

इकाई 4: प्राकृतिक वनस्पति एवं वन्य जीवन (4 Marks)
वनस्पति के प्रकार, ऊँचाई के अनुसार वानस्पतिक विविधता, प्रमुख वन्य जीव प्रजातियाँ और उनका वितरण, संरक्षण की आवश्यकता और विभिन्न उपाय। मध्य प्रदेश में पाये जाने वाले जीव-जन्तु, राष्ट्रीय उद्यान एवं अभ्यारण्य।

इकाई 5: जनसंख्या (5 Marks)
वितरण, लिंगानुपात, साक्षरता तथा राष्ट्रीय जनसंख्या नीति का परिचय।

इकाई 6: मानचित्र-पठन एवं अंकन (5 Marks)

इकाई 7: प्राचीन भारत (10 Marks)
सरस्वती-सिन्धु सभ्यता, वैदिक सभ्यता, मौर्यकाल, गुप्तकाल, हर्ष एवं पूर्व मध्यकाल का संक्षिप्त राजनीतिक परिचय।

इकाई 8: मध्यकालीन भारत (10 Marks)
अरब, गजनी और गौरी के आक्रमण, दिल्ली सल्तनत एवं मुगलकाल का संक्षिप्त परिचय, विजयनगर एवं बहमनी साम्राज्य, महाराणा प्रताप, रानी दुर्गावती तथा महाराजा शिवाजी का संक्षिप्त इतिहास, मुगलों का पतन।

इकाई 9: प्रमुख सांस्कृतिक प्रवृत्तियाँ (10 Marks)
प्रारम्भिक इतिहास से लेकर मुगलों के पतन तक भारत की प्रमुख सांस्कृतिक प्रवृत्तियाँ-साहित्य, चित्रकला, वास्तुकला, मूर्तिशिल्प, नृत्य, संगीत एवं अन्य ललित कलाएँ।

इकाई 10: प्रजातन्त्र की अवधारणा (6 Marks)
अर्थ एवं परिभाषा, आधारभूत सिद्धान्त, प्रकार एवं महत्व। भारत में प्रजातन्त्र का विकास-प्राचीन भारत में प्रजातन्त्र की अवधारणा, प्रजातन्त्र के लिये संविधान की आवश्यकता एवं महत्व।

इकाई 11: निर्वाचन (7 Marks)
दलीय व्यवस्था- अर्थ एवं महत्व, भारतीय चुनाव प्रक्रिया एवं चुनाव आयोग की भूमिका, मताधिकार- अर्थ एवं परिभाषा, मताधिकार प्राप्त करने की शर्ते।

इकाई 12: नागरिकों के संवैधानिक अधिकार एवं कर्तव्य (7 Marks)
संविधान द्वारा प्रदत्त मौलिक अधिकार, मौलिक कर्त्तव्य, सूचना का अधिकार।

इकाई 13: ग्रामीण अर्थव्यवस्था का विकास (6 Marks)
प्राचीन भारत की ग्राम आधारित अर्थव्यवस्था का परिचय, आदर्श ग्राम की अवधारणा, मध्य प्रदेश के किसी ग्राम का आर्थिक अध्ययन।

इकाई 14: भारत के समक्ष आर्थिक चुनौतियाँ (8 Marks)
गरीबी-अर्थ, कारण, गरीबी निवारण के कुछ प्रमुख कार्यक्रम, विभिन्न प्रकार के ग्रामीण, लघु, मध्यम, भारी एवं आधारभूत उद्योगों की भारत में स्थिति।

इकाई 15: खाद्य सुरक्षा (6 Marks)
अनाज-भारत में अनाजों के प्रकार, खाद्य सुरक्षा क्यों? शासन एवं सहकारिता की भूमिका, लोक वितरण प्रणाली, राशन की दुकान।

MP Board Class 9th Social Science Marking Scheme

इकाई क्र. इकाई का नाम कालखण्ड अंक
1. पर्यावरण 12 08
2. भारत: स्थिति, प्राकृतिक विभाग 06 04
3. जलवायु एवं अपवाह तन्त्र 06 04
4. प्राकृतिक वनस्पति एवं वन्य जीवन 05 04
5. जनसंख्या 08 05
6. मानचित्र-पठन एवं अंकन 05 05
7. प्राचीन भारत 14 10
8. मध्यकालीन भारत 14 10
9. प्रमुख सांस्कृतिक प्रवृत्तियाँ 15 10
10. प्रजातन्त्र की अवधारणा 10 06
11. निर्वाचन 12 07
12. नागरिकों के संवैधानिक अधिकार एवं कर्तव्य 14 07
13. ग्रामीण अर्थव्यवस्था का विकास 12 06
14. भारत के समक्ष आर्थिक चुनौतियाँ 15 08
15. खाद्य सुरक्षा 12 06
पुनरावृत्ति 20
कुल योग (पूर्णांक) 100

MP Board Class 9th Social Science Syllabus in English Medium

1. Man and Environment: (08 Marks)
Meaning of environment, Elements and Importance, Natural and cultural. Man and environment relationship, types and effect of environmental pollution, corrective measures. Ecological degradation and changing patterns of land use, Factors responsible for this. Population growth, Industrialisation and Urbanisation. Transport, Encroachment on water bodies. Facilities for tourism, pilgrimage, Recreation and adventure, Construction of large dams. Mining and war, Resources of Natural environment, utilization and conservation.
Some success stories of environmental conservation e.g., C.N.G., Chipko Movement, Silent Valley, Water Harvesting. Role of Environmental Impact Assesment (EIA).

2. India: Situation, Physical Division (04 Marks)
Geographical Situation of India, Physical division.

3. Climate & Drainage Pattern (04 Marks)
Factors affecting climate, Monsoon and its Characteristic, Rainfall and Temperature Distribution, Effect of Weather and Climate on Human Life.
Rivers: Major & Minor, Lakes and Seas, Role of Rivers in Economic Development of the Country, River Pollution and measures for control.

4. Natural Vegetation and Wild Life (04 Marks)
Types of Vegetation, Altitudinal Variation Vegetation, Major wildlife species, and their distribution, need & various measures for conservation Wild Animals, National Parks and Sanctuaries of Madhya Pradesh.

5. Population (05 Marks)
Distribution, Sex Ratio, Literacy & Introduction to National Population Policy.

6. Map: Study and Depiction (05 Marks)

7. Ancient India: (10 Marks)
Indus Valley Civilization, Vedic Civilization, Mauryan Period, Gupta Period, Brief introduction to the political history of Harsha period.

8. Medieval India (10 Marks)
Invasion of the Arabs, Ghazni and Ghori. Delhi Sultanate and a brief introduction to the Mughal period. Vijayanagar and Bahamani Empires, a brief history of Maharana Pratap. Rani Durgawati and Maharaja Shivaji, fall of the Mughals

9. Major Cultural Trends (10 Marks)
From the early history to the fall of the Mughals. Literature, Painting. Architecture, Sculpture, Dance and Music etc.

10. Concept of Democracy (06 Marks)
Meaning and Definition, Basic Principles, Types and Importance. ,
Evolution of Democracy in India: Concept of Democracy in ancient India. Necessity & Importance of Constitution for democracy.

11. Election (07 Marks)
Party System: Meaning and Importance; Indian Electoral Process and the Role of Election Commission;
Voting rights: Meaning & Definition, Conditions for acquiring voting right.

12. Constitutional Rights and Duties of Citizen (07 Marks)
Fundamental Rights granted by the Constitution; Fundamental duties.

13. Development of Rural Economy (06 Marks)
An introduction to Village-based economy in ancient India. Concept of Ideal Village, A study of Village economy in Madhya Pradesh.

14. Economic Challenges Facing India (08 Marks)
Poverty: Meaning, Causes, Poverty alleviation Programme, Various Types of Heavy Medium, Small and Cottage Industries in India.

15. Food Security (06 Marks)
Varieties of food grains in India, Need of Food Security, Role of Government, Public distribution System and Fair Price Shops.

MP Board Class 9th Social Science Marking Scheme in English Medium

Unit Subject content/Lesson Marks Period
1. Man and Environment 04 06
2. Conservation of Environment 04 06
3. India: Location. Physical Division 04 06
4. Drainage System 02 02
5. Climate 02 04
6. Natural Vegetation and Wild Life 04 05
7. Population 05 08
8. Map Study and Depiction 05 05
9. Ancient India 10 14
10. Medieval India 10 14
11. Major Cultural Trends 10 15
12. Democracy 06 10
13. Election 07 12
14. Constitutional Rights and Duties of Citizens 07 14
15. Rural Economy 06 12
16. Poverty: An Economic challenge for India 04 07
17. State of Industries in India 04 08
18. Food Security 06 12
Revision 20
Total 100 180

We hope the given MP Board Class 9th Social Science Solutions Guide Pdf Free Download सामाजिक विज्ञान in both Hindi Medium and English Medium will help you. If you have any query regarding Madhya Pradesh Syllabus MP Board Class 9 Social Science Book Solutions Samajik Vigyan Pdf, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Hindi Solutions वासंती, नवनीत

MP Board Class 9th Hindi Solutions Guide Pdf Free Download of हिंदी वासंती, नवनीत are part of MP Board Class 9th Solutions. Here we have given Madhya Pradesh Syllabus MP Board Class 9 Hindi Book Solutions Vasanti, Navneet Pdf Special and General.

MP Board Class 9th Hindi Book Solutions Vasanti

Here we have given MP Board Class 9 General Hindi Vasanti Solutions Hindi Samanya Kaksha 9 (वासंती हिंदी सामान्य कक्षा 9).

Vasanti Hindi Book Class 9 Solutions

MP Board Class 9 General Hindi व्याकरण

MP Board Class 9th Hindi Book Solutions Navneet

Here we have given MP Board Class 9 Special Hindi Navneet Solutions Hindi Vishisht Kaksha 9 (नवनीत हिंदी विशिष्ट कक्षा 9).

Navneet Hindi Book Class 9 Solutions

पद्य साहित्य

गद्य साहित्य

एकांकी

कहानी

MP Board Class 9 Special Hindi सहायक वाचन Solutions

MP Board Class 9 Special Hindi व्याकरण

MP Board Class 9 General Hindi Syllabus & Marking Scheme

क्रम विषय सामग्री अंक कालखंड
1. पद्य खंड
-एक पद्यांश की व्याख्या
-काव्य-सौंदर्य पर आधारित प्रश्न
-विषय वस्तु
25 40
2. गद्य खंड
अर्थ ग्रहण संबंधी विषय वस्तु पर आधारित प्रश्न
25 40
3. हिन्दी साहित्य का इतिहास
काल विभाजन (सामान्य परिचय)
05 10
4. व्याकरण
उपसर्ग, प्रत्यय
वर्तनी संशोधन
तत्सम, तद्भव, देशज शब्द
पर्यायवाची शब्द, अनेकार्थी शब्द,
विलोम शब्द वाक्यांश के लिए एक शब्द
वाक्य शुद्ध करना, मुहावरे/लोकोक्तियाँ
20 30
5. अपठित बोध
पद्यांश/गद्यांश-शीर्षक सारांश एवं प्रश्न
10 15
6. पत्र-लेखन 05 10
निबन्ध लेखन 10 15
पुनरावृत्ति 20
योग 100 180

MP Board Class 9 Special Hindi Syllabus & Marking Scheme

क्रम विषय सामग्री अंक कालखंड
1. पद्य खण्ड –
पद्य साहित्य का विकास
कवि परिचय, व्याख्या, सौन्दर्य बोध तथा
भाव एवं विषय वस्तु पर आधारित प्रश्न
4 + 23 = 27 40
2. गद्य खण्ड –
गद्य की विविध विधाएँ
लेखक परिचय, व्याख्या, गद्य पाठों पर आधारित
विचार बोध एवं विषय बोध पर प्रश्न
4 + 19 = 23 35
3. सहायक वाचन –
विविध पाठों पर आधारित प्रश्न
आँचलिक भाषा के पाठों पर आधारित प्रश्न
10 15
4. भाषा बोध-
उपसर्ग, प्रत्यय, तत्सम, तद्भव, देशज, आगत शब्द, रूढ़, यौगिक, योग रूढ़, वर्तनी परिचय एवं सुधार, पर्यायवाची, विलोम, अनेकार्थी शब्द मुहावरे एवं लोकोक्तियों का अर्थ प्रयोग
10 15
5. काव्य बोध-
काव्य की परिभाषा एवं भेद – मुक्तक काव्य, प्रबंध काव्य
रस – परिभाषा, अंग, भेद, उदाहरण
अलंकार – अनुप्रास, यमक, श्लेष, उपमा, रूपक, उत्प्रेक्षा
छंद – परिभाषा, मात्रिक, वर्णिक, दोहा, चौपाई
10 15
6. अपठित बोध 05 10
7. पत्र लेखन 05 10
8. निबंध लेखन 10 20
पुनरावृत्ति 20
योग 100 180

निर्धारित पाठ्यपुस्तक – “नवनीत”
(गद्य पद्य संकलन) सहायक वाचन समाहित

पद्य खण्ड- (27 Marks)

  • पद्य साहित्य का विकास : आदिकाल (वीरगाथा काल) एवं भक्ति काल, सामान्य परिचय पर प्रश्न (4 Marks)
  • पद्य पाठों पर आधारित कवि का संक्षिप्त साहित्यिक परिचय पर प्रश्न (रचनाएँ, काव्यगत विशेषताएँ) (5 Marks)
  • दो में से एक पद्यांश की सप्रसंग व्याख्या (5 Marks)
  • सौन्दर्य बोध पर आधारित प्रश्न (7 Marks)
  • भाव एवं विषय वस्तु पर आधारित प्रश्न (6 Marks)

गद्य खण्ड- (23 Marks)

  • गद्य की विविध विधाओं का सामान्य परिचय पर आधारित प्रश्न (4 Marks)
  • लेखक का संक्षिप्त परिचय पर प्रश्न (रचनाएँ, भाषा, शैली) (5 Marks)
  • दो में से एक गद्यांश की प्रसंग सहित व्याख्या (5 Marks)
  • गद्य पाठों पर आधारित विचार बोध पर प्रश्न (5 Marks)
  • विषय बोध पर प्रश्न (4 Marks)

सहायक वाचन- (पाठ्य पुस्तक में समाहित) (10 Marks)

  • संकलित पाठों की विषय वस्तु पर प्रश्न

भाषा बोध- (10 Marks)

  • उपसर्ग/ प्रत्यय पर आधारित प्रश्न (2 Marks)
  • तत्सम, तद्भव, देशज, आगत, रूढ़, यौगिक, योगरूढ, शब्द पर प्रश्न (2 Marks)
  • वर्तनी परिचय/वर्तनी सुधार पर प्रश्न (2 Marks)
  • पर्यायवाची/विलोम/अनेकार्थी पर प्रश्न (2 Marks)
  • मुहावरे/लोकोक्तियाँ – अर्थ एवं प्रयोग पर प्रश्न (2 Marks)

काव्य बोध- (10 Marks)

  • काव्य की परिभाषा – भेद, मुक्तक काव्य, प्रबन्ध काव्य (खण्ड काव्य, महा काव्य) पर प्रश्न (4 Marks)
  • रस – परिभाषा, अंग, भेद, उदाहरण पर आधारित प्रश्न (2 Marks)
  • अलंकार – अनुप्रास, यमक, श्लेष, उपमा, रूपक, उत्प्रेक्षा पर प्रश्न (2 Marks)
  • छंद – मात्रिक, वर्णिक, दोहा, चौपाई छंद पर प्रश्न (2 Marks)

अपठित बोध- (5 Marks)

  • गद्यांश-शीर्षक, सारांश/प्रश्न पर प्रश्न
  • पद्यांश- शीर्षक, सारांश/प्रश्न पर प्रश्न

पत्र लेखन- (5 Marks)

  • पारिवारिक, विद्यालयीन, आवेदन पत्र, पर प्रश्न

निबन्ध लेखन- (10 Marks)

  • वर्णनात्मक, विवरणात्मक, एवं समसामयिक विषयों पर निबन्ध लेखन पर प्रश्न

प्रायोजना कार्य-

  • क्षेत्रीय बोली-पहेलियाँ, चुटकुले, लोकगीत, लोक कथाओं का परिचय तथा खड़ी बोली में उनका अनुवाद।
  • दूरदर्शन/आकाशवाणी के कार्यक्रम पर प्रतिक्रियाएँ/विश्लेषण।
  • हिन्दी साहित्य का स्वतंत्र पठन/टिप्पणी एवं प्रेरणाएँ।
  • हस्त लिखित पत्रिका तैयार करना।
  • म.प्र. से प्रकाशित होने वाली हिन्दी भाषा की पत्र पत्रिकाओं की जानकारी।

टिप्पणी-
प्रायोजना कार्य से सम्बन्धित विषय वस्तु पर(अंक आवंटित न होने के कारण) परीक्षा में प्रश्न पूछे जाना अपेक्षित नहीं है।
निर्धारित पाठ्यपुस्तक – “नवनीत” (गद्य पद्य संकलन) सहायक वाचन समाहित
मध्यप्रदेश राज्य शिक्षा केन्द्र द्वारा संकलित एवं निर्मित तथा मध्यप्रदेश पाठ्यपुस्तक निगम द्वारा प्रकाशित

MP Board Class 9 General Hindi Blue Print of Question Paper

You can download MP Board Class 9th Hindi Blueprint and Marking Scheme 2019-2020 in Hindi and English medium.

MP Board Class 9 Hindi Blue Print of Question Paper 1

MP Board Class 9 Special Hindi Blue Print of Question Paper

MP Board Class 9 Hindi Blue Print of Question Paper 2

We hope the given MP Board Class 9th Hindi Solutions Guide Pdf Free Download of हिंदी वासंती, नवनीत will help you. If you have any query regarding Madhya Pradesh Syllabus MP Board Class 9 Hindi Book Solutions Vasanti, Navneet Pdf Special and General, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Sanskrit Solutions दूर्वा

MP Board Class 9th Sanskrit Solutions Guide Pdf Free Download संस्कृत दूर्वा are part of MP Board Class 9th Solutions. Here we have given Madhya Pradesh Syllabus MP Board Durva Sanskrit Book Class 9 Solutions Pdf.

MP Board Class 9th Sanskrit Book Solutions Durva

Durva Sanskrit Book Class 9 Solutions

MP Board Class 9th Sanskrit व्याकरणखण्डः

We hope the given MP Board Class 9th Sanskrit Solutions Guide Pdf Free Download संस्कृत दूर्वा will help you. If you have any query regarding Madhya Pradesh Syllabus MP Board Class 9 Sanskrit Book Solutions Durva Pdf, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Science Solutions विज्ञान

MP Board Class 9th Science Solutions Guide Pdf Free Download विज्ञान in both Hindi Medium and English Medium are part of MP Board Class 9th Solutions. Here we have given NCERT Madhya Pradesh Syllabus MP Board Class 9 Science Book Solutions Vigyan Pdf.

MP Board Class 9th Science Solutions विज्ञान
MP Board Class 9th Science Solutions विज्ञान

MP Board Class 9th Science Book Solutions in Hindi Medium

MP Board Class 9th Science Book Solutions in English Medium

We hope the given MP Board Class 9th Science Solutions Guide Pdf Free Download विज्ञान in both Hindi Medium and English Medium will help you. If you have any query regarding NCERT Madhya Pradesh Syllabus MP Board Class 9 Science Book Solutions Vigyan Pdf, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Maths Solutions गणित

MP Board Class 9th Maths Solutions Guide Pdf Free Download गणित in both Hindi Medium and English Medium are part of MP Board Class 9th Solutions. Here we have given NCERT Madhya Pradesh Syllabus MP Board Class 9 Maths Book Solutions Ganit Pdf.

MP Board Class 9th Maths Solutions गणित
MP Board Class 9th Maths Solutions गणित

MP Board Class 9th Maths Book Solutions in Hindi Medium

MP Board Class 9th Maths Chapter 1 संख्या पद्धति

MP Board Class 9th Maths Chapter 2 बहुपद

MP Board Class 9th Maths Chapter 3 निर्देशांक ज्यामिति

MP Board Class 9th Maths Chapter 4 दो चरों वाले रैखिक समीकरण

MP Board Class 9th Maths Chapter 5 युक्लिड के ज्यामिति का परिचय

MP Board Class 9th Maths Chapter 6 रेखाएँ और कोण

MP Board Class 9th Maths Chapter 7 त्रिभुज

MP Board Class 9th Maths Chapter 8 चतुर्भुज

MP Board Class 9th Maths Chapter 9 समान्तर चतुर्भुज और त्रिभुजों के क्षेत्रफल

MP Board Class 9th Maths Chapter 10 वृत्त

MP Board Class 9th Maths Chapter 11 रचनाएँ

MP Board Class 9th Maths Chapter 12 हीरोन का सूत्र

MP Board Class 9th Maths Chapter 13 पृष्ठीय क्षेत्रफल एवं आयतन

MP Board Class 9th Maths Chapter 14 सांख्यिकी

MP Board Class 9th Maths Chapter 15 प्रायिकता

MP Board Class 9th Maths Book Solutions in English Medium

MP Board Class 9th Maths Chapter 1 Number systems

MP Board Class 9th Maths Chapter 2 Polynomials

MP Board Class 9th Maths Chapter 3 Coordinate Geometry

MP Board Class 9th Maths Chapter 4 Linear Equations in Two Variables

MP Board Class 9th Maths Chapter 5 Introduction to Euclid’s Geometry

MP Board Class 9th Maths Chapter 6 Lines and Angles

MP Board Class 9th Maths Chapter 7 Triangles

MP Board Class 9th Maths Chapter 8 Quadrilaterals

MP Board Class 9th Maths Chapter 9 Areas of Parallelograms and Triangles

MP Board Class 9th Maths Chapter 10 Circles

MP Board Class 9th Maths Chapter 11 Constructions

MP Board Class 9th Maths Chapter 12 Heron’s Formula

MP Board Class 9th Maths Chapter 13 Surface Areas and Volumes

MP Board Class 9th Maths Chapter 14 Statistics

MP Board Class 9th Maths Chapter 15 Probability

We hope the given MP Board Class 9th Maths Solutions Guide Pdf Free Download गणित in both Hindi Medium and English Medium will help you. If you have any query regarding NCERT Madhya Pradesh Syllabus MP Board Class 9 Maths Book Solutions Ganit Pdf, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules

MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules

Atoms and Molecules Intext Questions

Atoms and Molecules Intext Questions Page No. 32 – 33

Question 1.
In a reaction 5.3g of sodium carbonate reacted with 6g of ethanoic acid. The products were 2.2g of carbon dioxide. 0. 9g water and 8.2g of sodium ethanoate. Show that these observations are in agreement with the law of co serration of mass.
Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water
Answer:
The reaction is,
Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water
5.3g + 6g → 8.2g + 2.2g + 0.9g
Now,
Total mass of reactants = (5.3 + 6)g = 11.3g
And, total mass of products = (8.2 + 2.2 + 0.9)g = 11.39g
So, Mass of reactants = Mass of product
It shows the law of conservation of mass.

MP Board Solutions

Molar Mass Calculator with steps for Chemistry Problems – determine the molar mass of a compound based on its formula.

Question 2.
Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3g of hydrogen gas?
Answer:
Ratio of hydrogen and oxygen in water = 1 : 8
So, oxygen is 8 times that of hydrogen by mass.
Let, xgrams of oxygen will react with 3g of hydrogen.
Then,
1 : 8 = 3 : x
x = 8 × 3
x = 24g
∴ 24g of oxygen gas required.

Question 3.
Which postulate of Dalton’s atomic theory is the result of the law of conservation of mass?
Answer:
Postulate of Dalton’s theory based on law of conservation of mass is “Atoms are indivisible particles which can neither be created nor be destroyed in a chemical reaction.”

Question 4.
Which postulate of Dalton’s atomic theory can explain the law of definite proportions?
Answer:
Postulate is the relative number and kinds of atoms remain constant in a given compound.

The mole to mass calculator tool calculates the mass of compound required to achieve a specific molar concentration and volume.

Atoms and Molecules Intext Questions Page No. 35

Question 1.
Define the atomic mass unit.
Answer:
Atomic mass unit is the mass unit equal to \(\frac { 1 }{ 12 }\)th mass of one carbon-12 atom.

Question 2.
Why is it not possible to see an atom with naked eyes?
Answer:
The size of an atom is very very small that we can see with naked eyes. The size of an atoms lies in nano meters (nm).

Atoms and Molecules Intext Questions Page No. 39

Question 1.
Write down the formulae of:
(i) Sodium oxide
(ii) Aluminium chloride
(iii) Sodium sulphide
(iv) Magnesium hydroxide.
Answer:
(i) Sodium Oxide

  • Symbol → NaO
  • Charge → +1-2
  • Formula → Na2O

(ii) Aluminium Chloride

  • Symbol → AlCl
  • Charge → +3-1
  • Formula → AlCl3

(iii) Sodium Sulphate

  • Symbol → NaS
  • Charge → +1-2
  • Formula → Na2S

(iv) Magnesium Hydroxide

  • Symbol → MgOH
  • Charge → +2-1
  • Formula → Mg(OH)2

MP Board Solutions

Question 2.
Write down the names of compounds represented by the following formulae:

  1. Al2(SO4)3
  2. CaCl2
  3. K2SO4
  4. KNO3
  5. CaCO3

Answer:

  1. Al2(SO4)3 → Aluminium sulphate
  2. CaCl2 → Calcium chloride
  3. K2SO4 → Potassium sulphate
  4. KNO3 → Potassium nitrate
  5. CaCO3 → Calcium carbonate

Question 3.
What is meant by the term chemical formula?
Answer:
It is the representation of composition of a compounds in the form of symbols of elements present in it.

Question 4.
How many atoms are present in a:

  1. H2S molecule and
  2. PO43- ion?

Answer:

  1. H2S Molecule -2 atoms of H + 1 atom of S = Total 3 atoms.
  2. PO43- 1 atom of phosphorus + 4 atoms of oxygen total 5 atoms.

Atoms and Molecules Intext Questions Page No. 40

Question 1.
Calculate the molecular masses of:

  1. H2
  2. O2
  3. Cl2
  4. CO2
  5. CH4
  6. C2H6
  7. C2H4
  8. NH3
  9. CH3OH.

Answer:

  1. H2 = (2 × 1)u = 2u
  2. O2 = (2 × 16)u = 32u
  3. Cl2 = (2 × 35.5)u = 71u
  4. CO2 = (1 × 12 + 2 × 16)u = (12 + 32)u = 44u
  5. CH4 = (1 × 12 + 4 × 1)u = (12 + 4)u = 16u
  6. C2H6 = (2 × 12 + 6 × 1)u = (24 + 6)u = 30u
  7. C2H4= (2 × 12 + 4 × 1)u = (24 + 4)u = 28u
  8. NH3 = (1 × 14 + 3 × 1)u = (14 + 3)u = 17u
  9. CH3OH = (1 × 12 + 3 × 1 + 1 × 16 + 1 × 1)u = (12 + 3 + 16 + 1)u = 32u.

Question 2.
Calculate the formula unit masses of ZnO, Na2O, K2CO3, given atomic masses of Zn = 65u, Na = 23u, K = 39u, C = 12u and O = 16u.
Answer:
Formula unit mass of

  1. ZnO = (1 × 65 + 1 × 16)u = (65 + 16)u = 81u
  2. Na2O = (2 × 23 + 1 × 16)u = (46 + 16)u = 62u
  3. K2CO3 = (2× 39 + 1 × 12 + 3 × 6)u = (78 + 12 + 48)u = 138u

Atoms and Molecules Intext Questions Page No. 42

Question 1.
If one mole of carbon atoms weighs 12 gram, what is the mass (in gram) of 1 atom of carbon?
Answer:
1 mole of carbon atoms = 6.022 × 1023 atoms
Also, 1 mole of carbon atoms = 12g
6.022 × 1023 atoms of carbon weigh = 12g
1 atom of carbon weigh = 1.99 × 1023g.

Question 2.
Which has more number of atoms, 100 grams of sodium or 100 grams of ion (given atomic mass of Na = 23u, Fe = 56u)?
Answer:
1 mole of sodium = 23g of Na
Atoms = 6.022 × 1023 atoms
23g of Na = 6.022 × 1023 atoms
100g of Na = \(\frac { 100 }{ 23 }\) × 6.022 × 1023 = 2.617 × 1024 atoms 8 23
Now, 1 mole of iron atoms = 56g of Fe = 6.022 × 1023 atoms
56g of Fe = 6.022 × 1023 atoms
100g of Fe = \(\frac { 100 }{ 56 }\) × 6.022 × 1023 = 1.075 × 1024 atoms
So, 100 g of Na contains more atoms.

Atoms and Molecules NCERT Textbook Exercises

Question 1.
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096g of boron and 0.144g of oxygen. Calculate the percentage composition of the compound by weight.
Answer:
Percentage composition of boron
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 1
Percentage composition of oxygen
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 2

Question 2.
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.00g of oxygen? Which law of chemical combination will govern your answer?
Answer:
We know that 3g of carbon is burnt in 8g of oxygen to form 11g of carbon dioxide.
When 3g of carbon is burnt in 50g of oxygen, then 11g of carbon dioxide will be formed.
And oxygen remain unreacted, (50 – 8)g = 42g.
Law of constant proportion governs here.

Question 3.
What are polyatomic ions? Give examples.
Answer:
The ions which contain more than one type of atoms (same kind or different kinds) as a single unit are called polyatomic ions.
Examples:

  • Sulphate ion (SO4-2)
  • Nitrate ion (NO3-2)
  • Carbonate ion (CO3-2).

Question 4.
Write the chemical formulae for the following:
(a) Magnesium chloride
(b) Calcium oxide
(c) Copper nitrate
(d) Aluminium chloride
(e) Calcium carbonate.
Answer:
(a) Magnesium chloride – MgCl2
(b) Calcium oxide – CaO
(c) Copper nitrate – Cu(NO3)2
(d) Aluminium chloride – AlCl3
(e) Calcium carbonate – CaCO3

MP Board Solutions

Question 5.
Give the names of the elements present in the following compounds:
(a) Quick lime
(b) Hydrogen bromide
(c) Baking powder
(d) Potassium sulphate
Answer:
(a) Quick lime (calcium oxide): Elements: Calcium and oxygen.
(b) Hydrogen bromide: Elements: Hydrogen and bromide.
(c) Baking powder (sodium hydrogen carbonate) Elements: Sodium, hydrogen, carbon, oxygen.
(d) Potassium sulphate: Elements: Potassium, sulphur, oxygen.

Question 6.
Calculate the molar mass of the following substances:
(a) Ethyne, C2H2
(b) Sulphur molecule, S8
(c) Phosphorus molecule, P4 (Atomic mass of phosphorus = 31)
(d) Hydrochloric acid, HCl
(e) Nitric acid, HNO3.
Answer:
(a) Ethyne, C2H2 = (2 × 12 + 2 × 1)g = (24 + 2)g = 26g
(b) Sulphur molecules, S8 = (8 × 32)g = 256g
(c) Phosphorus molecule, P4 = (4 × 31)g = 124g
(d) Hydrochloric acid, HCl = (1 × 1 + 1 × 35.5)g = (1 + 35.5)g = 36.5g
(e) Nitric acid, HNO3 = (1 × 1 + 1 × 14 + 3 × 16)g = (1 + 14 + 48)g = 63g

Question 7.
What is the mass of:
(a) 1 mole of nitrogen atoms?
(b) 4 moles of aluminium atoms (Atomic mass of aluminium = 27)?
(c) 10 moles of sodium sulphite (Na2SO3)?
Answer:
(a) 1 Mole of nitrogen atoms = 14g.

(b) Mass of 1 mole of aluminium atoms = 27g.
So, mass of 4 moles of aluminium atoms = (4 × 24)g = 108g.

(c) Mass of 1 mole of sodium sulphide
= (2 × 23 + 32 × 1 + 3 × 16)g = (46 + 32 + 48)g = 126g
∴ Mass of 10 moles of Na2SO3 = (126 × 10)g = 1260g.

Question 8.
Convert into mole:
(a) 12g of oxygen gas
(b) 20g of water
(c) 22g of carbon dioxide.
Answer:
(a) Mass of oxygen gas = 12g
Now, 1 mole of oxygen gas = 32g moles mass
So, 32g molar mass of oxygen = 1 moles
∴ 1g of oxygen gas = \(\frac { 1 }{ 32 }\) moles
and 12 g of oxygen gas = \(\frac { 1 }{ 32 }\) moles × 12 moles = 0.375 moles.

(b) 1 Mole of water = 18g molar mass
So, 18g moles mass of water = 1 mole
∴ 1g of water = \(\frac { 1 }{ 18 }\) moles
and 20 g of water = \(\frac { 1 }{ 18 }\) moles × 20 moles = 1.11 moles.

(c) 1 Mole of carbon dioxide = 44g molar mass
So, 44g molar mass of = 1 mole carbon dioxide
∴ 22g of carbon dioxide = \(\frac { 22 }{ 44 }\) moles = 0.5 mole.

MP Board Solutions

Question 9.
What is the mass of
(a) 0.2 mole of oxygen atoms?
(b) 0.5 mole of water molecules?
Answer:
(a) 1 mole of oxygen atoms = 16g
∴ 0.2 moles of oxygen atoms = (16 × 0.2)g = 3.2g

(b) 1 mole of water molecules = 18g
∴ 0.5 mole of water molecule = (18 × 0.5)g = 9g.

Question 10.
Calculate the number of molecules of sulphur (S8) present in 16g of solid sulphur.
Answer:
256g of sulphur = 1 mole of sulphur molecules
So, 16g of sulphur = \(\frac { 1 }{ 16 }\) × 16 moles of sulphur molecules
= 0.0625 mole of sulphur molecule
Also, 1 mole of sulphur molecules = 6.023 × 1023 molecules
So, 0.0625 moles of sulphur molecules = 6.025 × 1023 × 0.0625 molecules
= 3.76 × 1022 molecules.

Question 11.
Calculate the number of aluminium ions present in 0.051g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27u).
Answer:
Molar mass of aluminium oxide (Al2O3) = (2 × 27)g + (3 × 16)g
= (54 + 48)g = 102g
∴ 102g of aluminium = 6.022 × 1023 oxide contains aluminium ions
So, 0.051g Al2O3 contains aluminium ions = 6.022 × 1020 aluminium ions.

Atoms and Molecules Additional Questions

Atoms and Molecules Multiple Choice Questions

Question 1.
Atomic theory of matter was proposed by.
(a) Newton
(b) John Dalton
(c) Rutherford
(d) Lavoisier.
Answer:
(b) John Dalton

Question 2.
Law of Conservation of mass was given by.
(a) Lavoisier
(b) Dalton
(c) Kennedy
(d) Faraday.
Answer:
(a) Lavoisier

Question 3.
The term mole was first introduced by.
(a) Grahm
(b) Dalton
(c) Ostwald
(d) Boyle.
Answer:
(c) Ostwald

Question 4.
Atomic radius of an atom is measured in.
(a) Micrometre
(b) Millimetre
(c) Nanometre
(d) Centimetre.
Answer:
(c) Nanometre

Question 5.
Law of constant proportions was proposed by.
(a) Dalton
(b) Bezelius
(c) Proust
(d) Lavoisier.
Answer:
(c) Proust

Question 6.
Latin name of an atom is argentum. The English name of this element is.
(a) Argon
(b) Gold
(c) Silver
(d) Mercury.
Answer:
(c) Silver

Question 7.
Phosphorus molecule is.
(a) Diatomic
(b) Triatomic
(c) Tetra – atomic
(d) Mono – atomic.
Answer:
(c) Tetra – atomic

MP Board Solutions

Question 8.
The atom chosen for reference for measuring atomic masses is.
(a) C-14
(b) C-12
(c) H-2
(d) O-12.
Answer:
(b) C-12

Question 9.
IUPAC is.
(a) Indian Union of Pacific and Applied Chemistry.
(b) International Union of Permanent and Applied Chemicals.
(c) International Union of Pure and Applied Chemistry.
(d) Indian Union of Pure and Applied Chemistry.
Answer:
(c) International Union of Pure and Applied Chemistry.

Question 10.
Atomic mass is measured in.
(a) Grams
(b) Atomic mass radius
(c) Centigrams
(d) Atomic mass unit.
Answer:
(d) Atomic mass unit.

Question 11.
1 A.M.U. is equal to.
(a) 1.65 × 10-23g
(b) 1.63 × 10-25g
(c) 1.66 × 10-24g
(d) 1.66 × 10-22g.
Answer:
(c) 1.66 × 10-24g

Question 12.
The naming of elements from first or first and second letter was introduced by.
(a) Berzellius
(b) Dalton
(c) Proust
(d) Lavoisier.
Answer:
(a) Berzellius

Question 13.
The combining capacity of an element is called.
(a) Atomicity
(b) Valency
(c) Reactivity
(d) None of these.
Answer:
(b) Valency

Question 14.
The cation of element has.
(a) More electrons than normal atom
(b) Equal electrons than normal atom
(c) Less electrons than normal atom
(d) Equal proton than normal atom.
Answer:
(c) Less electrons than normal atom

Question 15.
The formula of a compound is A5B4. Then valency of A and B will be.
(a) 5 and 4
(b) 5 and 9
(c) 4 and 9
(d) 4 and 5.
Answer:
(d) 4 and 5.

Question 16.
1 Mole has.
(a) 6.012 × 1023 particles
(b) 6.022 × 1023 particles
(c) 6.022 × 1022 particles
(d) 6.022 × 1025 particles
Answer:
(b) 6.022 × 1023 particles

Question 17.
Which of the following has the maximum number of atoms?
(a) 18g of CH4
(b) 18g of H4O
(c) 18g of CO2
(d) 18g of O2.
Answer:
(a) 18g of CH4

Question 18.
Atomic mass of C6H12O6 is.
(a) 24
(b) 80
(c) 100
(d) 12
Answer:
(a) 24

Question 19.
1 atomic mass unit is equal to.
a) \(\frac { 1 }{ 14 }\) mass of a C – 12 atom
(b) \(\frac { 1 }{ 16 }\)mass of a C – 12 atom
(c) \(\frac { 1 }{ 18 }\) mass of a C – 12 atom
(d) \(\frac { 1 }{ 12 }\)mass of a C – 12 atom.
Answer:
(d) \(\frac { 1 }{ 22 }\)mass of a C – 12 atom.

Question 20.
Atomicity of Sulphate (SO42-) ion.
(a) Mono – atomic
(b) Tri – atomic
(c) Poly – atomic
(d) Tetra – atomic
Answer:
(c) Poly – atomic

Question 21.
Formula of number of moles of a substance is.
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 3
Answer:
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 4

Atoms and Molecules Very Short Answer Type Questions

Question 1.
Name the scientist who gave atomic theory of matter.
Answer:
John Dalton.

Question 2.
Name the scientist who gave the law of conservation of mass.
Answer:
Antoine Lavoisier

MP Board Solutions

Question 3.
Name the scientist who gave the law of constant proportions.
Answer:
Joseph Proust.

Question 4.
How many metres are in 1nm?
Answer:
1nm = 10-9m.

Question 5.
Give two examples of polyatomic molecules of elements.
Answer:
P4 (Phosphorus) and S8 (Sulphur).

Question 6.
Write full form of IUPAC.
Answer:
International Union of Pure and Applied Chemistry.

Question 7.
An element A and B has valency of 3 and 4. Write its chemical formula.
Answer:
A4B3.

Question 8.
Name the scientist who introduced the term ‘mole’.
Answer:
Wilhem Ostwald.

Question 9.
How many particles exist in 1 mole of atom?
Answer:
1 mole = 6.022 × 1023 particles.

Question 10.
Write the formula of aluminium sulphate.
Answer:
Al2(SO4)3.

Question 11.
Name the charged particles formed by gaining of electrons.
Answer:
Anion.

Question 12.
Name the charged particles formed by loosening of electrons.
Answer:
Cation.

Question 13.
What is numerical value of Avogadro number or Avogadro’s constant?
Answer:
6.022 × 1023.

MP Board Solutions

Question 14.
Write the Latin names of iron, gold and copper.
Answer:

  1. Iron – Ferrum
  2. Gold – Aurum
  3. Copper – Cuprum.

Question 15.
What is 1 amu?
Answer:
1 amu = \(\frac { 1 }{ 2 }\)th mass of a carbon-12 atom.

Question 16.
Calculate the number of atoms of oxygen present in its 3.5 moles.
Answer:
1 mole of oxygen atoms = 6.022 × 1023
∴ 3.5 moles of oxygen atoms = 3.5 × 6.022 × 1023 atoms
= 2.10 × 1024 atoms.

Atoms and Molecules Short Answer Type Questions

Question 1.
Define:
(a) Law of conservation of mass.
(b) Law of constant proportions.
(c) Atomic mass.
(d) Molecules of element.
(e) Molecules of compound.
(f) Atomicity.
(g) Ion.
(h) Chemical formula.
(i) Valency.
(j) Molecular mass.
(k) Formula unit mass.
(l) Mole.
Answer:
(a) Law of conservation of mass: Matter is neither created nor destroyed during a chemical reaction i.e., total mass of reactants is equal to the total mass of products in a chemical reaction.

(b) Law of constant proportions: In a chemical compound, the elements are always present in a definite proportion by mass.
e.g.:

  • In CO2 the ratio of mass of carbon to the mass of oxygen is always 7 : 16.

(c) Atomic mass: The Atomic mass of an element is defined as the relative mass of its atom as compared with the mass of a carbon 12 atom taken as 12 units.

(d) Molecules of element: It contain two or more similar kinds of atoms chemically combined together.
e.g.:

  • O2, N2, P4.

(e) Molecules of compound: It contains two or more different kinds of atoms chemically combined together.
e.g.:

  • SO4, CO2, H2O.

(f) Atomicity: It is the total number of atoms present in a molecule.
e.g.:

  • Atomicity of H2 is 2
  • Atomicity of P4 is 4 and
  • Atomicity of CO2 is 3.

(g) Ion: It is the positively or negatively charged atom or group of atoms. It is formed by either loosening or gaining of electrons. Positively charged ion is called cation and negatively charged ion is called anion.
e.g.:

  • Cation – Na+, Mg2+, NH4+
  • Anion – Cl, Br,OH, SO42-

(h) Chemical formula: Chemical formula of a compound is representation in the form of symbols of elements present in it.
e.g.:

  • Sodium chloride (NaCl)
  • Calcium oxide (CaO).

(i) Valency: It is the combining power (or capacity) atom or group of atoms. It tells number of electrons lost or gained by the atom during the Chemical reaction.
e.g.:
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 5

(j) Molecular mass: It is the sum of atomic masses of all the atoms in a molecule of the substance.
e.g.:
Molecular mass of CO2 is = Atomic mass of C + 2 × atomic mass of O
= 12 + 2 × 16
= 12 + 32 = 44u
It is expressed in atomic mass unit (u).

(k) Formula unit mass: It is the sum of atomic masses of all atoms in a formula unit of the compound containing constituents as ions. It is also expressed in atomic mass unit (u).
e.g.:
Formula unit mass of NaCl = Atomic mass of Na + atomic mass of Cl.
= (1 × 23 + 1 × 35.5)u
= (23 + 35.5)u = 58.5u.

(l) Mole: One mole of any substance like atoms or molecules or ions is that quantity which has mass equal to its atomic or molecular mass in grams and also contains 6.022 x 1023 particles of that substance.
e.g.:
1 mole of H2 molecule = (1 × 2)g = 2g and also,
1 Mole of H2 molecule = 6.022 × 1023 molecules of hydrogen.

MP Board Solutions

Question 2.
Write the postulates of Dalton’s atomic theory.
Answer:
Postulates:

  1. All matter is made up of very tiny particles called atoms.
  2. Atoms are indivisible.
  3. Atoms can neither be created nor be destroyed in a chemical reaction.
  4. Atoms of a given element are identical in mass and chemical properties.
  5. Atoms combine in the ratio of small whole numbers to form compounds.
  6. The number of atoms and kind of atoms is fixed in a given compound.

Question 3.
What were the drawbacks of Dalton’s atomic theory?
Answer:
Drawbacks:

  1. According to theory, atoms were indivisible but they can be divided in ions in electrons, protons and neutrons under special conditions.
  2. According to theory, atoms of an element have masses but it is found that atoms of some elements can have some different masses.
  3. According to theory, atoms of different elements have different masses but it is found that atoms of different elements can have same masses.

Question 4.
Calcium carbonate decomposes on heating to form calcium oxide and carbon dioxide. When 20g calcium carbonate is decomposed completely then 11.2g of calcium oxide is formed. Calculate the mass of carbon dioxide formed. Which law of chemical combination will be applied there?
Answer:
Law of conservation of mass is applied here.
Now,
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 14
Let, x grams of CO2 is formed
Now, according to law of conservation of mass.
Total mass of reactants = Total mass of product
⇒ 20 = 11.2 + x
⇒ x = (20 – 11.2) = 8.89
So, Mass of CO2 formed is 8.8g.

Question 5.
In an experiment 9.8g of copper oxide was obtained from 7.84g of copper. In another experiment 9.1g of copper oxide was obtained on reduction 7.28g of copper. Show with the help of calculations that these figures verify the law of constant proportions.
Answer:
Case I:
Mass of copper oxide = 9.8g
Mass of copper = 7.84g
Mass = (9.8 – 7.84)g = 1.96g
So, Ratio of copper to oxygen = \(\frac { 7.84 }{ 1.96 }\) = \(\frac { 4 }{ 1 }\) = 4 : 1

Case II:
Mass of copper oxide = 9.1g
Mass of copper = 7.28g
∴ Mass of oxygen = (9.1 – 7.28)g = 1.82g
So, Ratio of copper to oxygen = \(\frac { 7.28 }{ 1.82 }\) = \(\frac { 4 }{ 1 }\) = 4 : 1
Since, ratio of copper and oxygen in the two samples is same.
The law of constant proportions is verified.

Question 6.
Write the atomicity of following compounds.
(a) H2O
(b) CaCO3
(c) H2SO4
(d) C6H12O6
(e) S8.
Answer:
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 6

Question 7.
Write the chemical formula of:
(a) Hydrogen oxide
(b) Calcium carbonate
(c) Magnesium chloride
(d) Aluminium sulphate
Answer:
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 7

Question 8.
Calculate the molecular ma
(a) CH3OH
(b) C6H12O6
(c) NH3
(d) H2SO4
Atomic masses:
C = 12u
H = 1u
O = 16u
N = 14u
S = 32u
Answer:
(a) Molecular mass of
CH3OH = (1 × 12 + 3 × 1 + 1 × 16 + 1 × 1)u
= (12 + 3 + 16 + 1 )u = 32u.

(b) Molecular mass of
C6H12O6 = (6 × 12 + 12 × 1 + 6 × 16)u
= (72 + 12 + 96)u = 180u.

(c) Molecular mass of
NH3 = (1 × 14 + 3 × 1)u
= (14 + 3)u = 17u.

(d) Molecular mass of
H2SO4 = (1 × 2 + 1 × 32 + 4 × 16)u
= (2 + 32 + 64)u
= 98u.

Question 9.
Calculate the number of molecules of:
(a) SO2 in its 3 moles.
(b) O2 in its 2.5 moles.
Answer:
(a) 1 mole of SO2 molecule
= 6.022 × 1023 molecules of SO4
= 3 moles of SO4 molecule
= 3 × 6.022 × 1023 molecules
= 18.066 × 1023 molecules.

(b) 1 mole of O2 molecule
= 6.022 × 1023 molecules of O2
= 2.5 moles of O2 molecule
= 2.5 × 6.022 × 1023 molecules of O2
= 15.055 × 1023 molecules
= 1.5055 × 1024 molecules.

MP Board Solutions

Question 10.
Calculate the number of moles in:
(a) 12.044 × 1023 molecules of CO2.
(b) 24.012 × 1024 molecules of H2
Answer:
(a) 1 mole of CO2 = 6.022 × 1023 particles of CO2.
⇒ 6.022 × 1023 particles = 1 mole of CO2.
So, 1 particle of CO2 molecule
= 1 / 6.022 × 1023 mole and,
12.044 × 1023 particles of CO2 molecules
= 1 / 6.022 × 1023 × 12.044 × 1023
= 12.044 × 1023 × 1 / 6.022 × 1023 moles = 2 moles.

(b) 1 mole of H2 contains = 6.022 × 1023 particles of H2 molecule
or 6.022 × 1023 particles of H2 = 1 mole of H2
1 particle of H2 molecule = 1 / 6.022 × 1023 mole of H2.
∴ 24.012 × 1023 particles of H2 = 1 / 6.022 × 1023 × 24.012 × 1023 moles of H2
= 3.98 moles of H2.

Atoms and Molecules Long Answer Type Questions

Question 1.
Calculate the ratio of following elements by mass in the given compound:
(a) Hydrogen and oxygen in water (H2O).
(b) Carbon and oxygen in carbon dioxide (CO2).
(c) Carbon and hydrogen in ethene (C2H4).
Answer:
(a) In H2O molecule,
Mass of H = 2 × 1g = 2g
Mass of O = 1 × 16g = 16g
So, Ratio of hydrogen and oxygen by mass = \(\frac { 2 }{ 16 }\) =\(\frac { 1 }{ 8 }\) = 3 : 8

(b) In CO2 molecule,
Mass of C= 1 × 12g = 12g
Mass of O = 2 × 16g = 32g
.;. Ratio of carbon and oxygen by mass = \(\frac { 12 }{ 32 }\) = 3 : 8

(c) In ethene (C2H4) molecule,
Mass of C = 2 × 12g = 24g
Mass of H = (4 × 1)g = 4g
Ratio of carbon and hydrogen by mass = \(\frac { 24 }{ 4 }\) = 6 : 1

Question 2.
Calculate the formula unit mass of the following Ionic Compounds:
(a) Sodium Chloride (NaCl)
(b) Calcium Oxide (CaO)
(c) Copper Sulphate (CuSO4)
(d) Calcium Nitrate [Ca(NO3)2]
[Atomic masses: Na = 23u, Cl = 35.5u, Ca = 40u, O = 16u, Cu = 63.5u, S = 32u, N = 14u]
Answer:
(a) Formula unit mass of NaCl Molecule = (1 × 23 + 1 × 35.5)u
= (23 + 35.5)u = 58.5u.

(b) Formula unit mass of CaO molecule = (1 × 40 + 1 × 16)u
= (40 + 16)u = 56u.

(c) Formula unit mass of CuSO4 = (1 × 63.5 + 1 × 32 + 4 × 16)u
= (63.5 + 32 + 64)u = 159.5u.

(d) Formula unit mass of [Ca(NO3)2]
= 1 × 40 + 2 [1 × 14 4 + 3 × 16]
= 40 + 2 [14 4 + 48]u
= (40 + 124)u
= 164u.
MOLE CONCEPT (Graus to uoles):

Question 3.
Find the number of moles in:
(a) 20g of H2O
(b) 140g of CO2
(c) 200g of CaCO3.
Answer:
(a) 1 mole of H2O = Molar mass of H2O
= (2 × 1 + 16)g
So, 1 Mole = 18g of H2O
or 18g of H2O = 1 Mole
1g of H2O = \(\frac { 1 }{ 18 }\) Mole
and, 20g of H2O = \(\frac { 1 }{ 18 }\) × 20 = 1.11 Mole

(b) 1 mole of CO2 = Molar mass of CO2 = (1 × 12 + 2 × 16)g
= (12 + 32)g = 44g
So, 1 mole = 44g of CO2
or 44g of CO2 = 1 mole
1 g of CO2 = \(\frac { 1 }{ 44 }\) mole
and, 140 g of CO2 = \(\frac { 1 }{ 44 }\) × 140 moles
= 3.18 moles.

(c) 1 mole of CaCO3 = Molar mass of CaCO3
= (1 × 40 + 1 × 12 + 3 × 16)g
= (40 + 12 + 48)g = 100g
So, 1 mole = 100g of CaCO3
or 100g of CaCO3 = 1 mole
1g of CaCO3 = \(\frac { 1 }{ 100 }\) mole
and, 200 g of CaCO3 = \(\frac { 1 }{ 100 }\) × 200 moles = 2 moles.
Moles to Grams

Question 4.
Calculate the mass in grams of:
(а) 3 moles of H2O
(b) 2 moles of H2SO4
(c) 1.5 moles of carbon atoms (C atom).
Answer:

(a) 1 mole of H2O = Molar mass of H2O
= (2 × 1 + 16)g of H2O
= 18g of H2O
∴ 3 mole of H2O = (3 × 18)g of H2O
H2O = 54g of H2O

(b)1 mole of H2SO4 = Molar mass of H2SO4
= (2 × 1 + 1 × 32 + 4 × 16)g = 98g
2 mole of H2SO4 = (2 × 98)g = 196g

(c) 1 mole of C atom = Molar mass of C atom = 12g
∴ 1.5 moles of C -atom = (1.5 × 12)g = 18g.
Moles to Number of Particles.

Question 5.
Calculate the number of particles in:
(a) 115g of H2O.
(b) 60g of CO2.
Answer:
(a) We know,
1 mole of H2O = molar mass of H2O
= (2 × 1 + 16)g = 18g
It means, 18g of H2O = 1 mole of CO2
1g of H2O = \(\frac { 1 }{ 18 }\) mole = 6.38 moles
Now, 1 mole of H2O = 6.022 × 1023 particles
6.38 moles of H2O = 6.38 x 6.022 × 1023 particles
= 3.84 × 1024 particles.

(b) We know,
1 mole of CO2 = Molar mass of CO2
= (12 + 2 × 16)g = (12 + 32)g = 44g
It means, 44g of CO2 = 1 mole of CO2
1g of CO2= \(\frac { 1 }{ 44 }\) mole of CO2
and, 60g of CO2 = \(\frac { 1 }{ 44 }\) × 60 moles of CO2
= 1.3636 moles
Number of Particles to Mass.

Question 6.
Calculate the mass of:
(a) O2 in its 36.48 × 1025 particles.
(b) NH3 in its 4.012 × 1024 particles.
Answer:
(a) We know,
1 mole of O2 = 6.023 × 1023 particles
or 6.023 × 1023 particles = 1 mole of O2
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 10

Now, We also know,
1 mole of O2 contains = molar mass of O2
So, 60.57 moles of O2 contains = 60.57 × 32g = 1938.49g.

(b) We know,
1 mole of ammonia (NH3) = 6.022 X 1023 particles
or 6.022 × 1023 particles of ammonia (NH3) = 1 mole
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 12
Now, We also know that
1 mole NH3 contains = Molar mass of NH3
= (14 + 3 × 1)g = (14 + 3)g
= 17g
So, 6.66 moles of NH3 contains = (6.66 × 17)g = 113.25g

MP Board Solutions

Question 7.
(a) Define atomicity and poly atomic ions.
(b) Find out the atomicity of following:
CO2, NH3, S8, CaCO3, H2SO4, Ca(OH)2, K2SO4, Al2(SO4)3, NaCl.
(c) Write 2 divalent and 2 trivalent polyatomic ions.
Answer:
(a) Atomicity: It is total number of atoms present in a molecule.
e,g.,

  • Atomicity of H2 is 2.

Polyatomic ions: Ions which are formed from group of atoms are called polyatomic ions.
e,g.,

  • Carbonate (CO32-), Sulphate (SO22-).

(b)
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 13

(c) Divalent polyatomic ions:

  • Carbonate ion (CO3s2-)
  • Sulphate ion (SO42-).

Trivalent polyatomic ions:

  • Phosphate ion (PO43-)
  • Phosphite ion (PO33).

Atoms and Molecules Higher Order Thinking Skills (HOTS)

Question 1.
A thermos P contains 0.5 mole of oxygen gas. Another thermos Q contain 0.4 mole of ozone gas. Which of the two thermos contain greater number of oxygen atom?
Answer:
1 molecule of oxygen (O2) = 2 atoms of oxygen
1 molecule of ozone (O3) = 3 atoms of oxygen
In thermos P:
1 mole of oxygen gas = 6.022 × 1023 molecules
0.5 mole of oxygen gas = 6.022 × 1023 × 0.5 molecules
= 6.022 × 1023 × 0.5 × 2 atoms
= 6.022 × 1023 atoms

In thermos Q:
1 mole of ozone gas = 6.022 × 1023 molecules
0.4 mole of oxygen gas = 6 .022 × 1023 × 0.4 molecules
= 6.022 × 1023 × 0.4 x 3 atoms
= 7.32 × 1023 atoms.

Question 2.
On analysing an impure sample of sodium chloride, the percentage of chlorine was found to be 45.5. What is the percentage of pure sodium chloride in the sample?
Answer:
Molecular mass of pure NaCl
= Atomic mass of Na + Atomic mass of Cl
= 23 + 35.5 = 58.5u
Precentage of chlorine in pure NaCl
Now, if chlorine is 60.6 parts
NaCl =100 parts
If chlorine is 45.5 parts,
Thus, percentage of pure NaCl = 75%.

Question 3.
Write the chemical formulae of the following:

  1. Ammonium phosphate
  2. Iron sulphate
  3. Calcium nitrate
  4. Magnesium nitride
  5. Ammonium sulphate
  6. Aluminium chloride
  7. Copper Nitrate
  8. Aluminium sulphate
  9. Sodium carbonate
  10. Barium chloride
  11. Calcium nitrate
  12. Potassium chloride
  13. Hydrogen sulphide
  14. Magnesium hydroxide
  15. Zinc sulphate.

Answer:

  1. Ammonium phosphate – (NH4)3PO4
  2. Iron sulphate – -Fe2(SO4)3
  3. Calcium nitrate – Ca(NO3)2
  4. Magnesium nitrate – Mg(NO3)2
  5. Ammonium sulphate – (NH4)2SO4
  6. Aluminium chloride – AlCl3
  7. Copper nitrate – CU(NO3)2
  8. Aluminium sulphate – Al2(SO4)3
  9. Sodium carbonate – Na2CO3
  10. Barium chloride – BaCl2
  11. Calcium nitrate – Ca(NO3)2
  12. Potassium chloride – KCl
  13. Hydrogen sulphide – H2S
  14. Magnesium hydroxide – Mg(OH)2
  15. Zinc sulphate – ZnSO4

Atoms and Molecules Value Based Question 

Question 1.
Jolly buys gold ornaments and she is told that the ornaments has 90% gold and the rest is copper. She has been given a bill which amounts 100% charges of gold. Jolly refused to pay
the bill for 100% gold but settles the bill for 90% gold?
(a) How many atoms of gold are present in 1 gram of gold?
(b) Find out the ratio of gold and copper in the ornaments.
(c) What value of Jolly is seen in the above discussion?
Answer:
(a) 1 gram of gold will contain \(\frac { 90 }{ 100 }\) = 0.9 g of gold.
MP Board Class 9th Science Solutions Chapter 3 Atoms and Molecules 9
∴ 0.046 mol of gold will contain = 0.046 × 6.022 × 1023 = 2.77 × 1021 atoms

(b) Ratio of gold : Copper 90 : 10

(c) Value of responsible behaviour and self – awareness is seen.

MP Board Class 9th Science Solutions

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India

MP Board Class 9th Social Science Chapter 18 Text Book Questions

Choose the Correct Answer:

Question 1.
Kharif crop is –
(a) Wheat
(b) Gram
(c) Paddy
(d) Oat.
Answer:
(c) Paddy

Question 2.
The part of Public Distribution System is –
(a) Shoe shop
(b) Gold & Silver shop
(c) Ration shop
(d) Grocery shop.
Answer:
(c) Ration shop

Question 3.
Target-ted public distribution is related to –
(a) Women
(b) Gents
(c) People living below the poverty line
(d) None of these.
Answer:
(c) People living below the poverty line

Question 4.
How much cereal is given under Antyodaya Anna Yojna –
(a) 5 kg
(b) 10 kg
(c) 15 kg
(d) 25 kg.
Answer:
(d) 25 kg.

MP Board Solutions

MP Board Class 9th Social Science Chapter 18 Very Short Answer Type Questions

Question 1.
Write the names of coarse cereal.
Answer:
Sorghum (Jowar), bajra (pearl millet) and maize.

Question 2.
In which years did India face famine?
Answer:
India had to face famine is the years 1835, 1877 and 1943.

Question 3.
What is Rojgar Ashwasan Yojna?
Answer:
Under Rojgar Ashwasan Yojna 100 days employment can be provided to 18 – 60 year old unskilled labor so that they are able to earn and purchase food grains through revamped public distribution system.

Question 4.
What is meant by minimum support price?
Answer:
Declaration of support price of agricultural crops means to give the guarantee of a minimum price to farmers for their crops.

Question 5.
Write the names of any two schemes launched for food security.
Answer:

  • Target-ted public distribution system
  • Kam Ke Badle Anaj Yojna.

MP Board Solutions

MP Board Class 9th Social Science Chapter 18 Short Answer Type Questions

Question 1.
What are the main factors of food security? Write about them.
Answer:
The main factors of food security are –

  • Availability of food to the whole population of the country.
  • Availability of enough money (purchasing power) to purchase the available food.
  • Food should be available to all at affordable prices.
  • The quality of the available food should be good.

To calculate the pH of a buffer, go to the buffer pH calculator.

Question 2.
What is Buffer Stock? Explain.
Answer:
if the production of food grains is less then to face such crisis of shortage and to distribute them through Public Distribution System, the stock of food grains kept by the government is known as Buffer Stock. Buffer Stock is the stock of food grains namely wheat and rice procured by government through Food Corporation of India (FCI).

The FCI purchases wheat and rice from farmers in states where there is surplus production. These food grains are stored in large granaries. It helps in resolving the problem of shortage of food grains during emergencies.

Question 3.
Explain Target-ted Public Distribution System.
Answer:
In 1997 target-ted Public Distribution System was introduced to ensure the availability of minimum quantity of food grains to families living below the poverty line. In this system food grains are provided to the poor on special low prices by issuing specific ration cards.

This is the largest food security plan of the world. In this system 3.5 kg. of food grains per month per family is being provided from 1st April, 2006. In the same way under the “Antyodaya Anna Yojna” 25 kg. of wheat at. Rs. 2/- per kg. and rice at Rs. 3/- per kg. is being provided to very poor families through Public Distribution System.

Under this system a differential price system was adopted including people below the poverty line (BPL) and also for people above the poverty line (APL)- in which prices of wheat and rice are fixed.

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Question 4.
What is Revamped Public Distribution System? Explain.
Answer:
Revamped Public Distribution System In January 1992, the Public Distribution System was amended and a revised Public Distribution System was introduced to supply essential goods to consumers of remote area, schedule tribes, backward classes, drought – affected and mountainous areas of the country. Its characteristics are as follows:

1. Preference has been given to the people of drought – affected areas, desert areas, mountainous area and slums in urban areas.

2. It is aimed at providing more quantity of food at comparatively low prices. Other than six chief essential commodities goods like tea, soap, pulse, iodized salt are included in it.

3. Rojgar Aswan Plan has been started in the development blocks included under this plan, in which 100 days employment can be provided tr 18 – 60 – year – old unskilled labor so that they are able to earn and purchase food-grains through Revamped Public Distribution System.

Question 5.
What is the role of cooperative in food security? Explain.
Answer:
In India the role of cooperative is very important in providing food security. This work is done by the consumer cooperative societies through the ration shops for the sale of food grains for the poor. In India there are different system of consumer cooperatives at national, state, district and village levels.

Out of these National Consumers. Cooperative (Federation) Ltd. is an organization at national level. State Cooperative Consumers’ Organization is affiliated to this forum (federation). There are 794 consumer cooperative stores at central level (wholesale) and 24,078 stores’at primary level.

In rural areas nearly 44,418 village level primary agricultural credit society are distributing essential goods along with their ordinary business. To fulfill the needs of consumers, consumer cooperative societies are running nearly 37,226 retail selling centers in urban and semi – urban areas.

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Question 6.
Differentiate between Kharif and Rabi Crops.
Answer:
Kharif:

  • Kharif crops are shown in June or early July and harvested at tire end of Monsoon. This means sowing is done at the onset of monsoon (June and July) while harvesting is done at the end of Monsoon (October and November).
  • Kharif crops are rice, jowar, maize, millet, groundnut, jute and cotton pulses are also grown in this session.
  • Kharif crops are of tropical climate. (Some changes in this pattern take place, see the note in bracketed column of rabi crop.)

Rabi:

  • Rabi crop season starts in November-December and hares – ting .takes place in the months of April and May.
  • the major rabi crops are – wheat, barley, gram,, linseed, rasped and mustard.
  • in the southern half of the Indian peninsula where temperatures are sufficiently high and rain occurs in winters this classification become blurred. Crops like Jowar are grown in.

MP Board Class 9th Social Science Chapter 18 Long Answer Type Questions

Question 1.
What are the major cereals of India? Describe.
Answer:
India is an agricultural country and the chief occupations is farming. Cereals are grown is about 70 to 80% of the total agricultural land. rice, wheat millers and maize are the major cereals.

1. Rice:
Rice is the staple food crap of India. It thrives well in hot and humid climate. It requires temperature of 25°C, and rainfall of 100 cm and above and loamy fertile soil. The chief rice producing areas in India are the coastal strips, the Gainga Plains, the Brahmaputra valley, the deltas of Godavari, Krishna and Kaveri.

High yielding varieties, improved planting techniques, irrigation facilities and use of fertilizers have enabled Sadie to increase the production of rice in 1985-86 to 61 million tonnes and average yield per hectare rose to 15.7 Quintilian (2 \(\frac { 1}{2}\) tonnes, increase)

2. Wheat:
Wheat is the second important food crop of India. It requires a cool and moist climate during growing season and a dry climate at the time of ripening. Annual rainfall of 50 to 75 cm and fertile and sandy soil is very suitable – The chief wheat growing areas are Punjab, Haryana IIP, Bihar, MP., Rajashtan Maharashtra, etc.

because all the conditions far wheat production are found here. The use of high yielding varieties,, fertilizers and irrigation facilities helped to raise fire average yield per acre and increased the production of wheat 51 million mark in 1985 – 89. This breakthrough in the production of wheat is called the Green Resolution.

3. Millets:
Sorghum (Jo-war) and bajra are important millets in India. Sorghum (Jowar) In India Jowar has been grown from ancient period. It is used as fodder for cattle and as a food for human beings. In India it is food of the poor, ha foreign countries it is used to prepare starch and glucose.

In northern India it is a Kharif crop but in southern India it is a crop of Kharif and Rabi both. About 87 percent of the total production of Jowar (sorghum) in the country is produced in Madhya Pradesh, Maharashtra, Karnataka and Andhra Pradesh.

4. Bajra:
It is a Kharif crop in northern India. In southern India it is a crop of Rabi and Kharif both. It is used as fodder for cattle. India is the largest producer of Bajra in the world, hi India main Bajra producing states are Rajasthan, Gujarat, Maharashtra, Uttar Pradesh, Tamilnadu, Haryana, Karnataka, Andhra Pradesh and Punjab. Of the total production of Bajra in the country 96 per cent is grown here.

5. Maize:
Maize is the crop of plains and mountainous region. It is used as fodder for cattle and as food to eat. Man uses its different varieties for food products. In foreign countries starch and glucose are prepared from this. In India it is grown in about all states but mainly it is grown in Uttar Pradesh, Punjab, Bihar, Madhya Pradesh, Rajasthan, Gujarat and Karnataka.

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Question 2.
What is food security and why is it necessary? Explain.
Answer:
Food security related to the food – related needs of man. In simple words food security means availability of nutritive food to all. Also people should have purchasing power (money) for the arrangement and availability of food at reasonable prices. According to the World Development Report, 1986 “Food security is the availability of adequate food at all time for active and healthy life for all”.

Necessity of Food Security:
In the present Indian situation food security has become very important. Our economy is developing but the population is also increasing rapidly. So to meet the increasing demand, food security has become necessary. The causes responsible for this can be divided into two parts internal causes and external causes.

I. Internal causes:
Internal causes include those which are related to the internal conditions of the country. Following factors are included in these.

1. Basis of life:
India is a country of large population and the birth rate is also very high. Therefore food security is necessary.

2. Dependence on Monsoon:
Majority of crops in India are dependent on monsoon for irrigation, but the monsoon is always uncertain and irregular. The distribution of rains is uneven too. Consequently droughts and famines are common features of our economy. Therefore food security is necessary.

3. Low Productivity:
In India the productivity of food grains regarding per hectare and per labor is low. From this point of view also food security is necessary.

4. Natural Calamities:
Other than the problem of monsoon, flood, insects and pets, cold waves, soil erosion etc. also destroy the food crops in some or the – other part of the country. So the problem of shortage of food crops arises. The famine in Orissa of 1835 in Punjab and Madhya Pradesh in 1877 and in West Bengal in 1943, lacks of people died of hunger. So food security is necessary to face these natural calamities.

5. Continuously Rising Prices:
The prices of food grains are increasing continuously which results in starvation. So food security is necessary to overcome this problem.

6. Progress of the Country:
No country can progress without self-sufficiency of food, and for this food security is necessary.

II. External causes:
External causes include those causes which are related to the relation of the other countries with our country. Following are the external causes:

1. Dependence on Foreign Countries:
Food is the basic need of human beings. So when this requirement is not fulfilled it becomes the primary duty of the Government to fulfill these needs of the people. If there is a shortage of food we have to depend on foreign countries. Whenever there is inadequate supply of food-grains in our country we have to import even if food graii are costly or cheap the quality is good or bad. Thus dependence on foreign countries increases.

2. Decrease in Foreign Exchange:
Whenever we import things like food grains we have to spend our foreign exchange unnecessarily. We can meet our demand for food ourselves but we cannot. This results in shortage of foreign exchange to purchase very important commodities.

3. Foreign Pressure:
Countries which supply food grains to other countries become influential and then they pursue them to follow their policies. These countries dominate those countries which import food grains from them, as a result they lose their freedom to decide their foreign policies.

In the year 1965 – 66 and 1966 – 67 due to the failure of monsoon India had to face a devastating drought and therefore wheat was imported from America. During these frequent emergencies of food grains India experienced that food security is very essential to save people from starvation, to protect self – respect that honor and sovereignty and for the development of the country.

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Question 3.
How does the government provide food security to the poor? Explain.
Answer:
Government provides food security to the poor through the following measures:

  1. Public Distribution System.
  2. Alertness of Government
  3. Measures taken in a Critical Situation.

1. Public Distribution System:
By Public Distribution System is meant that system in which different consumer goods are sold in sufficient quantity of fixed prices to the consumers specially to the poor section of society. In this system different goods such as wheat, rice, sugar, imported edible oil, coal and kerosene oil etc. are sold through ration shops or cooperative consumer stores.

The profit rate for these sellers ’are fixed and they have to sell the goods to the ration card holders on fixed price and in fixed quantities. There are three kinds of ration cards B.P.L. card, A.P.L card and Antyodaya cards. BPL cards are meant for those people who are below poverty line, APL cards are meant for those people who are above poverty line and Antyodaya cards are issued to those people who are the poorest of the poor.

The Public Distribution System is regulated by central and state government together. The central government allots food grains and other commodities to state and determines prices also. The state has the right to add transportation charges etc. to the prices fixed by Central Govt.

The transportation, collection, distribution and inspection of these goods processed under this system is done by state government. It is clear from the above table that Public Distribution System plays an important role in providing food-grains to people.

The state government can include those goods also in Public Distribution System which it can purchase if required. In India distribution of food-grains is increasing continuously through Public Distribution System as shown in the given table:

Public Distribution System and Distribution of Food Grains:

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 1

2. Alertness of Government:
Our government is very alert in providing food security to the poor. It has developed food security system to make food grains available at reasonable prices to the poor and other people.

3. Measures Taken in a Critical Situation:
The government takes several steps in order to make food grains available to the poor during the period of food crisis arising due to any other reasons or due to natural calamities. Some of these measures are given below:

I. Efforts to Increase Food Grains:
For food security it is important that the production of food grains should be enough in quantity. In this the contribution of green revolution is quite important under Green Revolution mechanization of agriculture, use of high yielding hybrid variety of seeds, fertilizers and insecticides and irrigation facilities were extended.

Also due to promotion of consolidation of land holdings, abolishing of mediators, today the country has become self-sufficient in the field of food grains. The progress of food grains in India can be explained on the basis of following table:

Food Grain Production in India (in crore tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 1

II. Minimum Support Price:
The prices of agriculture products are very flexible, at the time of harvesting the supply increases, due to which there is enough decrease in price. As prices at this time go down below the fixed limit the producer finds it difficult to get the cost of their products.

1. Therefore government declares minimum support price for agricultural products, under which when market price of food-grains becomes less than its support price, the government starts purchasing food grains on self-declared support price. Due to which farmers get inspired to produce more and more and the government procures food grain for “Buffer Stocks”.

2. The support prices declared by the government during last years are shown here in following table:

Support of Different Food Grains (Rupees per quintal):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 3

III. Buffer Stock:
If the production of food grains is less than to face such crisis of shortage and to distribute them through Public Distribution System, the stock of food grains kept by government is known as Buffer Stock. Buffer stock is the Stock of food grains, namely wheat and rice procured by government through Food Corporation of India (FCI).

The FCI purchases wheat and rice from farmers in states where there is surplus production. The farmers are paid a pronounced price for their crop. This price is called “Minimum Support Price”. The government declares these prices before the sowing season to provide incentives to farmers for raising production of these crops.

These food grains are stored in large granaries. It helps in resolving the problem of shortage of food grains during emergencies. The table of Buffer Stock explains that in the past years in India the stocks has been greater than fixed minimum quantity which is a sign of strong food security of India.

Status of Buffer Stock in India (in million tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 4

MP Board Solutions

Question 4.
What steps has the government taken to increase food grains?
Answer:

Government provides food security to the poor through the following measures:

  1. Public Distribution System.
  2. Alertness of Government
  3. Measures taken in a Critical Situation.

1. Public Distribution System:
By Public Distribution System is meant that system in which different consumer goods are sold in sufficient quantity of fixed prices to the consumers specially to the poor section of society. In this system different goods such as wheat, rice, sugar, imported edible oil, coal and kerosene oil etc. are sold through ration shops or cooperative consumer stores.

The profit rate for these sellers ’are fixed and they have to sell the goods to the ration card holders on fixed price and in fixed quantities. There are three kinds of ration cards B.P.L. card, A.P.L card and Antyodaya cards. BPL cards are meant for those people who are below poverty line, APL cards are meant for those people who are above poverty line and Antyodaya cards are issued to those people who are the poorest of the poor.

The Public Distribution System is regulated by central and state government together. The central government allots food grains and other commodities to state and determines prices also. The state has the right to add transportation charges etc. to the prices fixed by Central Govt.

The transportation, collection, distribution and inspection of these goods processed under this system is done by state government. It is clear from the above table that Public Distribution System plays an important role in providing food-grains to people.

The state government can include those goods also in Public Distribution System which it can purchase if required. In India distribution of food-grains is increasing continuously through Public Distribution System as shown in the given table:

Public Distribution System and Distribution of Food Grains:

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 1

2. Alertness of Government:
Our government is very alert in providing food security to the poor. It has developed food security system to make food grains available at reasonable prices to the poor and other people.

3. Measures Taken in a Critical Situation:
The government takes several steps in order to make food grains available to the poor during the period of food crisis arising due to any other reasons or due to natural calamities. Some of these measures are given below:

I. Efforts to Increase Food Grains:
For food security it is important that the production of food grains should be enough in quantity. In this the contribution of green revolution is quite important under Green Revolution mechanization of agriculture, use of high yielding hybrid variety of seeds, fertilizers and insecticides and irrigation facilities were extended.

Also due to promotion of consolidation of land holdings, abolishing of mediators, today the country has become self-sufficient in the field of food grains. The progress of food grains in India can be explained on the basis of following table:

Food Grain Production in India (in crore tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 1

II. Minimum Support Price:
The prices of agriculture products are very flexible, at the time of harvesting the supply increases, due to which there is enough decrease in price. As prices at this time go down below the fixed limit the producer finds it difficult to get the cost of their products.

1. Therefore government declares minimum support price for agricultural products, under which when market price of food-grains becomes less than its support price, the government starts purchasing food grains on self-declared support price. Due to which farmers get inspired to produce more and more and the government procures food grain for “Buffer Stocks”.

2. The support prices declared by the government during last years are shown here in following table:

Support of Different Food Grains (Rupees per quintal):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 3

III. Buffer Stock:
If the production of food grains is less than to face such crisis of shortage and to distribute them through Public Distribution System, the stock of food grains kept by government is known as Buffer Stock. Buffer stock is the Stock of food grains, namely wheat and rice procured by government through Food Corporation of India (FCI).

The FCI purchases wheat and rice from farmers in states where there is surplus production. The farmers are paid a pronounced price for their crop. This price is called “Minimum Support Price”. The government declares these prices before the sowing season to provide incentives to farmers for raising production of these crops.

These food grains are stored in large granaries. It helps in resolving the problem of shortage of food grains during emergencies. The table of Buffer Stock explains that in the past years in India the stocks has been greater than fixed minimum quantity which is a sign of strong food security of India.

Status of Buffer Stock in India (in million tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 4

MP Board Solutions

Question 5.
What is Public Distribution System and what are its main constituents? Describe.
Answer:
By Public Distribution System is meant that system in which different consumer goods are sold in sufficient quantity at fixed prices to the consumers specially to the poor section of society. In this system different goods (wheat, rice, sugar, imported edible oil, coal and kerosene oil etc.) are sold through ration shops or cooperative consumer stores.

The profit rate for these sellers are fixed and they have to sell the goods to the ration card holders on fixed price and in fixed quantities. There are three kinds of ration cards BPL Card, APL Card and Antyodaya Card. BPL cards are for people below poverty line. APL cards are for people above poverty line.

Antyodaya Cards are meant for the poorest of the poor. The Public Distribution System is regulated by central and state government together. The central government allots food grains and other commodities to state and determines prices also. The state has the right to add transportation charge etc.

to the prices fixed by Central Government. The transportation, collection, distribution and inspection of these goods processed under this system is-done by state government. The state government can include those goods also in Public Distribution System which it can purchase if required.

The main constituents of Public Distribution System. Public Distribution System includes fair-price shops. Fair Price Shop for selling cloth, soft coke depot, Super market and Kerosene shops. In India distribution of food grains is increasing continuously through Public Distribution System. The following table will show that Public Distribution system plays an important role in providing food grains to people.

Public Distribution System and Distribution of Food Grains (in million tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 5

MP Board Solutions

Question 6.
How is the Public Distribution System conducted? Describe.
Answer:

By Public Distribution System is meant that system in which different consumer goods are sold in sufficient quantity at fixed prices to the consumers specially to the poor section of society. In this system different goods (wheat, rice, sugar, imported edible oil, coal and kerosene oil etc.) are sold through ration shops or cooperative consumer stores.

The profit rate for these sellers are fixed and they have to sell the goods to the ration card holders on fixed price and in fixed quantities. There are three kinds of ration cards BPL Card, APL Card and Antyodaya Card. BPL cards are for people below poverty line. APL cards are for people above poverty line.

Antyodaya Cards are meant for the poorest of the poor. The Public Distribution System is regulated by central and state government together. The central government allots food grains and other commodities to state and determines prices also. The state has the right to add transportation charge etc.

to the prices fixed by Central Government. The transportation, collection, distribution and inspection of these goods processed under this system is-done by state government. The state government can include those goods also in Public Distribution System which it can purchase if required.

The main constituents of Public Distribution System. Public Distribution System includes fair-price shops. Fair Price Shop for selling cloth, soft coke depot, Super market and Kerosene shops. In India distribution of food grains is increasing continuously through Public Distribution System. The following table will show that Public Distribution system plays an important role in providing food grains to people.

Public Distribution System and Distribution of Food Grains (in million tonnes):

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India - 5

MP Board Solutions

MP Board Class 9th Social Science Chapter 18 Other Important Questions

Question 1.
Choose the right answer:
(i) Kharif crops are sown in the month of –
(a) October
(b) November
(c) December
(d) January
Answer:
(a) October

Question 2.
Rabi crops are harvested in the month of –
(a) February or March
(b) March or April
(c) April or May
(d) May or June.
Answer:
(b) March or April

Question 3.
In production of food grains India stands third after –
(a) America and Australia
(b) America and China
(c) America and Canada
(d) China and Canada.
Answer:
(b) America and China

Question 4.
Antyodaya ration cards are meant for those who are –
(a) Below poverty line
(b) Above poverty line
(c) Poorest of the poor
(d) None of the above.
Answer:
(c) Poorest of the poor

Question 5.
Target-ted Public Distribution System was introduced in the year –
(a) 1997
(b) 1998
(b) 1999
(d) 2000.
Answer:
(a) 1997

Fill in the blank:

  1. Reserve stock of food grains to meet …………… situations.
  2. ……………. cards for people below poverty line.
  3. ……………. cards for the poorest of the poor.
  4. In India two kinds of wheat are grown……………… and mikrani wheat.
  5. India is second largest producer of ………………… in the world.

Answer:

  1. Emergency
  2. BPL
  3. Antyodaya
  4. Walgair wheat
  5. Rice.

MP Board Solutions

MP Board Class 9th Social Science Chapter 18 Very Short Answer Type Questions

Question 1.
Name the main requirements of life?
Answer:
Food, clothing and housing.

Question 2.
How does the World Development Report 1986? Define Food security.
Answer:
According to the World. Development Report 1986, “Food security is the availability of adequate food at all time for active and healthy life for all”.

Question 3.
On what three factors does food security depend?
Answer:
Food security depends on three factors Public Distribution System, alertness of government and the measures taken in a situation of crisis.

Question 4.
Name the major cereals?
Answer:
The major Cereals are rice, wheat, mullets and maize.

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Question 5.
Name some rabi crops?
Answer:
Some rabi crops are wheat, oat, gram, etc.

Question 6.
Name rice producing states of India?
Answer:
Rice producing states of India are West Bengal, Uttar Pradesh, Andhra Pradesh, Chhattisgarh, Madhya Pradesh, Bihar, Tamil Nadu, Orissa, Punjab amd Assam.

Question 7.
When was Public Distribution System amended?
Answer:
Public Distribution System was amended in January 1992.

Question 8.
What are the parts of Public Distribution System?
Answer:
Public Distribution System includes fair price shops, soft coke depot, super market and kerosene shops.

Question 9.
Name two crops used as fodder for cattle?
Answer:
Jowar and Bajra.

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Question 10.
What type of economy have we?
Answer:
We have developing economy.

MP Board Class 9th Social Science Chapter 18 Short Answer Type Questions

Question 1.
What does food security generally imply? Mention the stages of food security?
Answer:
The food security generally implies that the whole population at all time, should have access to minimum quantity of cereals, but due to continuous changes in a developing country there can be following stages of food security:

  • Availability of adequate food grains.
  • Availability of food grains and pulses in adequate quantity.
  • Availability of milk and milk products along with food grains and pulses.
  • Availability of food-grains, pulses, milk and milk products, vegetables, fruits etc.

Question 2.
Describe the chief crops of India and their cultivation regions.
Answer:
The chief crops of India paddy (rice), wheat, bajra, jowar, maize, gram and pulses. Their cultivation regions

1. Paddy (rice):
West Bengal, Uttar Pradesh, Andhra Pradesh, Chhattisgarh, Madhya Pradesh, Bihar, Tamilnadu, Orissa, Punjab, Assam.

2. Wheat:
Uttar Pradesh, Punjab, Haryana, Madhya Pradesh, Bihar, Rajasthan, Maharashtra, West Bengal, Uttarakhand, Gujarat.

3. Bajra:
Rajasthan, Maharashtra, Tamilnadu, Punjab, Uttar Pradesh, Gujarat.

4. Jowar:
Madhya Pradesh, Maharashtra, Karnataka, Andhra Pradesh.

5. Maize:
Uttar Pradesh, Karnataka, Andhra Pradesh, Madhya Pradesh, Punjab, Bihar, Rajasthan.

6. Gram & Pulses:
Madhya Pradesh, Uttar Pradesh, Maharashtra, Punjab, Karnataka.

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Question 3.
What do you understand by ‘Fair Price Shop’? What are its benefits?
Answer:
Sugar, cereals, kerosene etc. are distributed to the ration card holders through ration shops which are also known as ‘Fair Price Shops’. Any family with a ration card can buy stipulated amount of these items, every month from nearby ration shop. At these shops all the items are sold at a price lower than the market price. Today there are about 4.6 lakh ration shops in the country.

Question 4.
Write a short note on Buffer Stock?
Answer:
If the production of food grains is less than to face such crises of shortage and to distribute them through Public Distribution System, the stock of food grains kept by government is known as Buffer Stock. Buffer Stock is the stock of food grains namely wheat and rice procured by government through Food Corporation of India (FCI).

The FCI purchases wheat and rice from farmers in states where there is surplus production. These food grains are stored in large granaries. It helps in resolving the problem of shortage of food grains during emergencies.

MP Board Class 9th Social Science Solutions Chapter 18 Food Security in India

Question 1.
Describe coarse crops.
Answer:
Sorghum (Jowar), bajra and maize are coarse crops.

1. Sorghum (Jowar):
Jowar is used as fodder for cattle and as food for human beings. In India it is food of the poor and in foreign countries it is used to prepare starch and glucose. About 87% of the total production of jowar in the country is produced in Madhya Pradesh, Maharashtra, Karnataka and Andhra Pradesh.

2. Bajra:
It is used as fodder for cattle. India is the largest producer of bajrai in the world. The main bajra producing states of India are Rajasthan, Gujarat, Maharashtra, Uttar Pradesh, Tamilnadu, Haryana etc. Of the total production of bajra in the country 96% is grown here.

3. Maize:
It is used as food and fodder. In India it is grown in about all states but mainly it is grown in Uttar Pradesh, Punjab, Bihar, Madhya Pradesh, Rajasthan, Gujarat and Karnataka.

MP Board Solutions

Question 2.
Why has food security become necessary in India? What are the causes responsible for this?
Answer:

Food security related to the food – related needs of man. In simple words food security means availability of nutritive food to all. Also people should have purchasing power (money) for the arrangement and availability of food at reasonable prices. According to the World Development Report, 1986 “Food security is the availability of adequate food at all time for active and healthy life for all”.

Necessity of Food Security:
In the present Indian situation food security has become very important. Our economy is developing but the population is also increasing rapidly. So to meet the increasing demand, food security has become necessary. The causes responsible for this can be divided into two parts internal causes and external causes.

I. Internal causes:
Internal causes include those which are related to the internal conditions of the country. Following factors are included in these.

1. Basis of life:
India is a country of large population and the birth rate is also very high. Therefore food security is necessary.

2. Dependence on Monsoon:
Majority of crops in India are dependent on monsoon for irrigation, but the monsoon is always uncertain and irregular. The distribution of rains is uneven too. Consequently droughts and famines are common features of our economy. Therefore food security is necessary.

3. Low Productivity:
In India the productivity of food grains regarding per hectare and per labor is low. From this point of view also food security is necessary.

4. Natural Calamities:
Other than the problem of monsoon, flood, insects and pets, cold waves, soil erosion etc. also destroy the food crops in some or the – other part of the country. So the problem of shortage of food crops arises. The famine in Orissa of 1835 in Punjab and Madhya Pradesh in 1877 and in West Bengal in 1943, lacks of people died of hunger. So food security is necessary to face these natural calamities.

5. Continuously Rising Prices:
The prices of food grains are increasing continuously which results in starvation. So food security is necessary to overcome this problem.

6. Progress of the Country:
No country can progress without self-sufficiency of food, and for this food security is necessary.

II. External causes:
External causes include those causes which are related to the relation of the other countries with our country. Following are the external causes:

1. Dependence on Foreign Countries:
Food is the basic need of human beings. So when this requirement is not fulfilled it becomes the primary duty of the Government to fulfill these needs of the people. If there is a shortage of food we have to depend on foreign countries. Whenever there is inadequate supply of food-grains in our country we have to import even if food graii are costly or cheap the quality is good or bad. Thus dependence on foreign countries increases.

2. Decrease in Foreign Exchange:
Whenever we import things like food grains we have to spend our foreign exchange unnecessarily. We can meet our demand for food ourselves but we cannot. This results in shortage of foreign exchange to purchase very important commodities.

3. Foreign Pressure:
Countries which supply food grains to other countries become influential and then they pursue them to follow their policies. These countries dominate those countries which import food grains from them, as a result they lose their freedom to decide their foreign policies.

In the year 1965 – 66 and 1966 – 67 due to the failure of monsoon India had to face a devastating drought and therefore wheat was imported from America. During these frequent emergencies of food grains India experienced that food security is very essential to save people from starvation, to protect self – respect that honor and sovereignty and for the development of the country.

MP Board Class 9th Social Science Solutions

MP Board Class 9th Solutions

MP Board Class 9th Books Solutions Guide Pdf download all subjects in both Hindi Medium and English Medium are part of MP Board Solutions. Here we have given NCERT Madhya Pradesh Syllabus MP Board Class 9 Text Book Solutions Pdf.

MP Board Class 9th Books Solutions

MP Board Class 9th Solutions
MP Board Class 9th Solutions

We hope the given MP Board Class 9th Books Solutions Guide Pdf download all subjects in both Hindi Medium and English Medium will help you. If you have any query regarding NCERT Madhya Pradesh Syllabus MP Board Class 9 Text Book Solutions Pdf, drop a comment below and we will get back to you at the earliest.

MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3

MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3

Question 1.
Draw the graph of each of the following linear equations in two variables:

  1. x + y = 4
  2. x – y = 2
  3. y = 3x
  4. 3 = 2x + y

solution:
1. x + y = 4
Take x = 1
1 + y = 4
∴ y = 3

Take x = 2,
2 + y = 4
∴ y = 2

Take x = 0,
0 + y = 4
∴ y = 4

The solutions are:
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-1
The graph is shown below.
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-2

2. x – y = 2
Take x = 1,
1 – y = 2
y = 2 – 1
∴ y = – 1

Take x = 2,
2 – y = 2
– y = 2 – 2
∴ y = 0

Take x = 0,
0 – y = 2
∴ y = – 2
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-3
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-4

3. y – 3x
Take x = 0,
y = 3 x 0 = 0

Take x = 1,
y = 3 x 1 = 3

Take x = 2,
y = 3 x 2 = 6
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-5

4. 3 = 2x + y
Take x = 1,
3 = 2 x 1 + y
3 = 2 + y
3 – 2 = y
∴ y = 1

Take x = 0
3 = 2 x 0 + y
∴ y = 3 – 0 = 3

Take x = -1,
3 = 2 x – 1 + y
3 = – 2 + y
∴ y = 3 + 2 = 5
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-6
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-7

Online nonlinear function calculator system of equations. Welcome to our step-by-step math Solve·

Question 2.
Give the equations of two lines passing through (2, 14). How many more such lines are there and why?
Solution:
Two lines passing through point (2, 14)

  1. x + y = 16
  2. 2x + y – 18

Infinitely many lines can be drawn through (2, 14).

MP Board Solutions

Question 3.
If the point (3, 4) lies on the graph of the equation 3y = ax + 7, find the value of a.
Solution:
Putting the value of x = 3 and y = 4 in 3y = ax + 7, we get
3 x 4 = a x 3 + 7
12 = 3a + 7
3a = 12 – 7
a = \(\frac{5}{3}\)

Question 4.
The taxi fare in a city is as follows: For the first kilometer, the fare is ₹ 8 and for the subsequent distance it is ₹ 5 per km. Taking the distance covered as x km and total fare as ₹ y, write a linear equation for this information and draw its graph.
Solution:
Distance covered = x km
Total fare = ₹ y
Fare of 1st km = ₹ 8
Fare for subsequent kms = ₹ 5 per km
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-8
According to question, y = 8 + 5 (x – 1) = 8 + 5x – 5
y = 3 + 5x
Take x = 0,
y = 3 + 5 x 0
∴ y = 3

Take x = 1,
y = 3 + 5 x 1
y = 3 + 5
∴ y = 8

Take x = 2
y = 3 + 5 x 2
∴ y = 13
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-9

Question 5.
From the choices given below, choose the equation whose graphs are given in Fig. (a) and Fig. (b)
For Fig. (a)
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-10

  1. y = x
  2. x + y = 0
  3. y = 2x
  4. 2 + 3y = 7x

For Fig. (b)
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-11

  1. y = x + 2
  2. y = x – 2
  3. y = – x + 2
  4. x + 2y = 6

Solution:
1. Since (-1, 1), (0, 0) and (1, -1) satisfies the equation x + y = 0.
The equation of the graph is x + y = 0

2. Since (-1,3), (0, 2) and (2, 0) satisfies the equation y = x + 2.
The equation of the graph is y = – x + 2.

MP Board Solutions

Question 6.
If the work done by a body on application of a constant force is directly proportional to the distance traveled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also read from the graph the work done when the distance traveled by the body is:

  1. 2 units
  2. 0 units.

Solution:
Let y be the work done and x be the distance covered. y ∝ x where k is the constant force.
y = kx, (Given)
k = 5
∴ y = 5x

Take x = 0
y = 5 x 0 = 0
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-12
Take x = 1
y = 5 x 1 = 5

Take = 2
y= 5 x 2 = 10
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-13
When the distance travelled is –

  1. x = 2 units y = 10 units
  2. x = 0 units y = 0 units.

Question 7.
Yamini and Fatima, two students of class IX of a school, to gether contributed ₹ 100 towards the Prime Minister’s Relief Fund to help the earthquake victims. Write a linear equation which satisfies this data. (You may take their contributions as ₹ x and ₹ y). Draw the graph of the same.
Answer:
Let the contribution of Yamini be ₹ x and that of Fatima be ₹ y.
According to question
x + y = 100
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-14
Take x = 30,
30 + y = 100
y = 100 – 30
y = 70

Take = 40,
40 + y = 100
y = 100 – 40
y = 60

Take = 50,
50 + y = 100
y = 100 – 50
y = 50
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-15

Question 8.
In countries like USA and Canada, temperature is measured in Fahrenheit, whereas in countries like India, it is measured in Celsius. Here is a linear equation that converts Fahren-heit to Celsius.
F = (\(\frac{9}{5}\)) C + 32

  1. Draw the graph of the linear equation above using Celsius for x – axis and Fahrenheit for y – axis.
  2. If the temperature is 30°C, what is the temperature in Fahrenheit?
  3. If the temperature is 95°F, what is the temperature in Celsius?
  4. If the temperature is 0°C, what is the temperature in Fahrenheit and if the temperature is 0°F, what is the temperature in Celsius?
  5. Is there a temperature which is numerically the same in both Fahrenheit and Celsius? If yes, find it.

1. F = \(\frac{9}{5}\) + 32
Take C = – 5,
F = \(\frac{9}{5}\) x (- 5) + 32
= – 9 + 32 = 23
C = – 10,
F = \(\frac{9}{5}\) x – 10 + 32 = 14
C = – 15,
F = \(\frac{9}{5}\) x – 15 + 32 = 5

2. From the graph, when temperature is 30°C, temperature in °F is 86°.

3. When F = 95°, C = 35°.
\(\frac{63×5}{9}\) = 35°

4. C = 0°, F = 32°
F = 0°, C = – 17.7°

5. F = – 40°, C = – 40°
MP Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.3 img-16

MP Board Class 9th Maths Solutions